Reputation: 63
I want to call a method of an abstract class from abstract class called by inherit class.
Abstract class:
public abstract class Abstract {
protected void updateMotionY(float deltaTime) {
System.out.println("Abstrcat updateMotionY");
}
public void update(float deltaTime) {
this.updateMotionY(deltaTime);
}
}
Inherit class:
public class Obj extends Abstract {
@Override
protected void updateMotionY(float deltaTime) {
System.out.println("updateMotionY");
super.updateMotionY(deltaTime);
}
@Override
public void update(float deltaTime) {
super.update(deltaTime);
}
}
Main method class:
public static void main(String[] args) {
(new Obj()).update(10.0f);
}
Whenever I try to call new Obj().update()
method in main class, it prints "updateMotionY" and "Abstrcat updateMotionY". I want to get only "Abstrcat updateMotionY".
Can anyone tell me how to resolve this problem?
Upvotes: 6
Views: 4397
Reputation: 140407
I think you are using abstract
in a very wrong way. Your base class should rather look like this:
public abstract class Abstract {
protected abstract void updateMotionY(float deltaTime);
public final void update(float deltaTime) {
this.updateMotionY(deltaTime);
}
}
Notes:
In other words: put the common parts solely in the base class, and make sure that you have to necessary abstract
methods in there to do that. But avoid implementing methods more than once. That only leads to confusion and strange bugs.
Upvotes: 4
Reputation: 352
You cannot create an instance of Abstract class so you're creating an instance of Obj class. Since your requirement is only to call method of Abstract class then why did you override the method updateMotionY
For your requirement this is what you need to do Abstract class:
public abstract class Abstract {
protected void updateMotionY(float deltaTime) {
System.out.println("Abstrcat updateMotionY");
}
public void update(float deltaTime) {
this.updateMotionY(deltaTime);
}
}
Inherit class:
public class Obj extends Abstract{
/*@Override
protected void updateMotionY(float deltaTime) {
System.out.println("updateMotionY");
super.updateMotionY(deltaTime);
}*/
@Override
public void update(float deltaTime) {
super.update(deltaTime);
}
}
I have commented the overridden code which will give you the required result. Also, the answer given by https://stackoverflow.com/users/8466177/steven-laan will also work.
Upvotes: 0
Reputation: 44090
(new Obj()).update(10.0f)
calls Obj::update
which calls Abstract::update
which calls this.updateMotionY
. Because this
is an instance of Obj
, this calls Obj::updateMotionY
.
This prints "updateMotionY".
This then calls super.updateMotionY(deltaTime)
which is Abstract::updateMotionY
.
This prints "Abstrcat updateMotionY".
That's the end of the call hierarchy and everything unwinds.
Fundamentally your confusion seems to stem from the fact that this.updateMotionY(deltaTime);
in the Abstract
class resolves to updateMotionY
in the Obj
class. That's basically the whole point of polymorphism.
One thing you could do is to add a private method (so that it cant be overridden) which contains the actual implementation, and defer to it:
public abstract class Abstract {
private void motionY(float dt)
{
System.out.println("Abstrcat updateMotionY");
}
protected void updateMotionY(float deltaTime) {
motionY(deltaTime);
}
public void update(float deltaTime) {
motionY(deltaTime);
}
}
Upvotes: 3
Reputation: 190
If you only want to execute the abstracts superclass' method, then the simple solution is to just call super.updateMotionY
instead of super.update
in your Obj class
public class Obj extends Abstract {
@Override
protected void updateMotionY(float deltaTime) {
System.out.println("updateMotionY: ");
super.updateMotionY(deltaTime);
}
@Override
public void update(float deltaTime) {
super.updateMotionY(deltaTime);
}
}
Upvotes: 0