Reputation: 1300
I'm trying to create little "recommended" functionality based on the posts with the most matching tags.
I got a layout like this:
Posts
id
---
1
2
3
4
post_tags
post_id | tag_id
---------+---------
1 | 1
1 | 2
2 | 2
2 | 3
2 | 4
3 | 1
3 | 2
3 | 4
4 | 5
tags
id
----
1
2
3
4
5
So if I would retrieve recommendations for the post with id 1 the list should go
3 (2/2 matches) 2 (1/2 matches) 4 (0/2 matches)
My Query so far looks like this:
SELECT DISTINCT
p.id,
p.title,
count(*) as cnt
FROM
posts p
INNER JOIN posts_tags pt ON pt.post_id= p.id
INNER JOIN tags t ON pt.tag_id = t.id
WHERE
t.id IN (
SELECT
pt.tag_id
FROM
posts_tags pt
WHERE
pt.post_id = '30213'
)
GROUP BY
t. NAME
order by count(*) desc
LIMIT 0, 4
I know DISTINCT
isn't working because of the count but I wanted to see just what he counted, so the result looks like this:
4 Foo 4881
4 Foo 2560
11 Bar 2094
12 Baz 1998
So what happened? It counted the occurences of the tag in general. So appearantly the first associated tag of "Post 1" is 4881 associated and then pulls the first entry that matches... the one with the lowest id.
I see the problem but I can't solve it.
Upvotes: 0
Views: 26
Reputation: 1270081
Your group by
makes no sense. You want to aggregate by the post not the tag:
SELECT p.id, p.title, count(*) as cnt
FROM posts p INNER JOIN
posts_tags pt
ON pt.post_id = p.id
WHERE pt.tag_id IN (SELECT pt2.tag_id
FROM posts_tags pt2
WHERE pt2.post_id = 30213
)
GROUP BY p.id, p.title
ORDER BY count(*) desc
LIMIT 0, 4;
This will not return 0
. If that is important, you need to use a LEFT JOIN
instead of WHERE . . . IN . . .
.
Also:
SELECT DISTINCT
is almost never used with GROUP BY
. It is hard (but not impossible) to come up with a use-case for it.tags
table, so I removed it.post_id
is really a number.GROUP BY
.Upvotes: 1