CODEWITHSUNDEEP
javastring
giovandrea
giovandrea

Reputation: 207

How to know if a String contains a specific set of characters in Java

I got a String which can contain:

I am trying to find a way to discriminate among those cases and, in particular, to be able to know if that String belongs ONLY to one case (i.e. if it contains plain text and numbers and other characters like "=" or "[" I'd like to put it in the first case, while if it contains ONLY number and "=" I'd like to put it in the second case).

I tried using something like:

if (text.contains("[") && text.contains("]") && text.contains(","))
      //other code

but in this case it could be both text and those characters or number and those characters, so I can't decide if I'm in the first or second case.

Thanks for your help.

Upvotes: 3

Views: 5434

Answers (2)

Titulum
Titulum

Reputation: 11486

This can easily be solved by using regex. Take a look here.

In your case: here are the regexes I would use:

only numbers and "=";

s.matches("[0-9|=]+");

only numbers and "[" "]" ",".

s.matches("[0-9\\[\\],]+");

And the first case is all the rest!

!s.isEmpty();

Upvotes: 4

Arun
Arun

Reputation: 3841

Go for regex

For numbers:

System.out.println(data.matches("[0-9]+"));

For numbers and '='

System.out.println(data.matches("[0-9=]+"));

For numbers and square brackets and , 

System.out.println(data.matches("[0-9\\[\\],]+") );

For plain text:

   System.out.println(data.matches("[a-zA-Z]+"));

where data is your input text

Upvotes: 3

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