CODEWITHSUNDEEP
phpif-statementcompare
Kjellson
Kjellson

Reputation: 47

Comparing two strings in percent: if $a % of $b

I need a short if/else in PHP to compare two strings in percent:

if ($sum['cur'] 70% of $sum['max']) {
    print ("Attention");
} else {
    print ("OK");
};

$sum['cur'] and $sum['max'] are numbers. For example, if $sum['max']=100 and $sum['cur']=80, I'd like to print a warning that 80% are in use.

Upvotes: 1

Views: 244

Answers (1)

Don't Panic
Don't Panic

Reputation: 41810

Assuming $sum['cur'] and $sum['max'] are numeric, it doesn't matter whether they're numeric strings or actual numbers. PHP will automatically convert them to the necessary type when you try to do math operations on them or compare them to numbers.

$percentage = 0.7;

if ($sum['cur'] / $sum['max'] >= $percentage) {
    print ("Attention");
} else {
    print ("OK");
};

If you need to display the actual percentage, you can calculate it beforehand rather than in the condition so that it can be used in the printed message. Since you're doing division, you may end up with some long decimal portion in the result. You can use printf to format that as needed.

$threshold = 70;

$percentage = $sum['cur'] / $sum['max'] * 100;

if ($percentage >= $threshold) {
    printf("Attention: %d%% percent are in use", $percentage);
} else {
    echo "OK";
};

Upvotes: 3

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