Brian Dolan
Brian Dolan

Reputation: 3136

Create / manipulate diagonal matrices in Chapel

I have a square matrix A

use LinearAlgebra;    
proc main() {
  var A = Matrix(
       [4.0, 0.8, 1.1, 0.0, 2.0]
      ,[0.8, 9.0, 1.3, 1.0, 0.0]
      ,[1.1, 1.3, 1.0, 0.5, 1.7]
      ,[0.0, 1.0, 0.5, 4.0, 1.5]
      ,[2.0, 0.0, 1.7, 1.5, 16.0]
      );
}

And I want to construct the diagonal matrix D = 1/sqrt(a_ii). It seems like I have have to extract the diagonal, then operate on each element. I expect this matrix is be very large and sparse, if that changes the answer.

Upvotes: 2

Views: 96

Answers (3)

ben-albrecht
ben-albrecht

Reputation: 1865

Here's a solution using the LinearAlgebra module in 1.16 (pre-release):

use LinearAlgebra;

var A = Matrix(
               [4.0, 0.8, 1.1, 0.0, 2.0],
               [0.8, 9.0, 1.3, 1.0, 0.0],
               [1.1, 1.3, 1.0, 0.5, 1.7],
               [0.0, 1.0, 0.5, 4.0, 1.5],
               [2.0, 0.0, 1.7, 1.5, 16.0]
              );

var S = sqrt(1.0/diag(A));

// Type required because of promotion-flatting
// See Linear Algebra documentation for more details..
var B: A.type = diag(S);

writeln(B);

Upvotes: 2

Brad
Brad

Reputation: 4008

Here's some code that works with a sparse diagonal array in version 1.15 today without linear algebra library support:

config const n = 10;   // problem size; override with --n=1000 on command-line

const D = {1..n, 1..n},                        // dense/conceptual matrix size
      Diag: sparse subdomain(D) = genDiag(n);  // sparse diagonal matrix

// iterator that yields indices describing the diagonal
iter genDiag(n) {
  for i in 1..n do
    yield (i,i);
}

// sparse diagonal matrix
var DiagMat: [Diag] real;

// assign sparse matrix elements in parallel
forall ((r,c), elem) in zip(Diag, DiagMat) do
  elem = r + c/10.0;

// print sparse matrix elements serially
for (ind, elem) in zip(Diag, DiagMat) do
  writeln("A[", ind, "] is ", elem);

// dense array
var Dense: [D] real;

// assign from sparse to dense
forall ij in D do
  Dense[ij] = DiagMat[ij];

// print dense array
writeln(Dense);

Upvotes: 1

user3666197
user3666197

Reputation: 1

Did you try this approach?

use Math;
var D: [A.domain];
forall      i in D.dim( 1 ) {
        D[i,i] = 1 / Math.sqrt( A[i,i] ); // ought get fused-DIV!0 protection
}

( A.T.M. <TiO>-IDE has not so far fully functional the LinearAlgebra package, so cannot show you the results live, yet hope you would enjoy the way forwards )

Upvotes: 1

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