CODEWITHSUNDEEP
pythonsockets
Willothy
Willothy

Reputation: 441

"[Errno 10048] Only one usage of each socket address (protocol/network address/port) is normally permitted" after closing and reopening Python socket

I have this code:

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
    s.bind(('10.0.0.253', 8080))
except:
    s.close()
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    s.bind(('10.0.0.253', 8080))


s.listen(1)
conn, addr = s.accept()

which binds, then if it encounters an error with that, destroys the socket then creates a new one and binds it to the same IP and port. For some reason, even after closing the socket, I get this error:

Traceback (most recent call last):
File "C:\Users\other\Desktop\tcpReverseShell_Server.py", line 68, in <module>
  main()
  File "C:\Users\other\Desktop\tcpReverseShell_Server.py", line 66, in main
  connect()
File "C:\Users\other\Desktop\tcpReverseShell_Server.py", line 43, in connect
  s.bind(('10.0.0.253', 8080))
File "C:\Python27\lib\socket.py", line 228, in meth
  return getattr(self._sock,name)(*args)
error: [Errno 10048] Only one usage of each socket address (protocol/network 
address/port) is normally permitted

The only solution I've found is to use s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1), but when I try that I get this error: [Errno 10013] An attempt was made to access a socket in a way forbidden by its access permissions. I

I am on Windows 10, Python 2.7.13.

Upvotes: 9

Views: 45806

Answers (2)

Amey Chavan
Amey Chavan

Reputation: 9

I face this issue many times , it happens mostly when your terminal crashes due to a network issue, or some other internal error.

solution :- find the port is listening or not and terminate it manual through your command prompt (CMD)

  • Step 1: ctrl+R
  • Step 2: type there : netstat -ano | find "5005"

note: enter the port surrounded by double-quotes: "port number"]

  • step 3:
    something like this will appear:
TCP    0.0.0.0:5005           0.0.0.0:0              LISTENING       12112

here "12112" is process ID

  • step 4: enter: taskkill /F /PID 12112

12112 is process ID , don't give double-quotes here

The following will be displayed by system:

SUCCESS: The process with PID 12112 has been terminated
  • step 5: Now try again issue will be solved

If it still gives error then restart the system and try again.

Upvotes: 1

Moon Cheesez
Moon Cheesez

Reputation: 2701

I can simulate your problem by running the python script twice concurrently. The problem is that some other application is currently also using the socket.

In your code, the except block is triggered when your socket fails to bind. However, when you try to .close() the socket and try again, it does nothing as it is trying to .close() an unbound socket. Hence, your code is equivalent to:

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('10.0.0.253', 8080))

s.listen(1)
conn, addr = s.accept()

Note that when you .close() the socket, it also does not .close() the currently bound application, it attempts to .close() to socket object you created. So, trying to bind the socket again will fail.

To find out what is using the socket, you can use netstat:

netstat -aon | findstr :8080

This should give you something like:

TCP    127.0.0.1:8080         0.0.0.0:0              LISTENING       6604

Then, if you want to kill it forcefully, you can use TaskKill and the application's PID:

TaskKill /PID 6604 /F

Upvotes: 12

Related Questions