Reputation: 216
I have a table with 50k records. Now I want to update one column of the table with a random number. The number should be 7 digits.
I don't want to do that with procedure or loop.
PinDetailId PinNo
--------------------
783 2722692
784 9888648
785 6215578
786 7917727
I have tried this code but not able to succeed. I need 7 digit number.
SELECT
FLOOR(ABS(CHECKSUM(NEWID())) / 2147483647.0 * 3 + 1) rn,
(FLOOR(2000 + RAND() * (3000 - 2000) )) AS rn2
FROM
[GeneratePinDetail]
Upvotes: 2
Views: 624
Reputation: 4081
For a random number, you can use ABS(CHECKSUM(NewId())) % range + lowerbound
:
(source: How do I generate random number for each row in a TSQL Select?)
INSERT INTO ResultsTable (PinDetailId, PinNo)
SELECT PinDetailId,
(ABS(CHECKSUM(NewId())) % 1000000 + 1000000) AS `PinNo`
FROM GeneratePinDetail
ORDER BY PinDetailId ASC;
I cannot guarantee these will be unique; but it should be evenly distributed (equal chance of any 7 digit number). If you want to check for duplicates you can run this:
SELECT PinDetailId, PinNo
FROM ResultsTable result
INNER JOIN (
SELECT PinNo
FROM ResultsTable
GROUP BY PinNo
HAVING Count(1) > 1
) test
ON result.PinNo = test.PinNo;
Upvotes: 2
Reputation: 553
You can create a sequence object and update your fields - it should automatically increment per update.
https://learn.microsoft.com/en-us/sql/t-sql/functions/next-value-for-transact-sql
Updated based on comment: After retrieving the 'next value for' in the sequence, you can do operations on it to randomize. The sequence can basically be used then to create a unique seed for your randomization function.
If you don't want to create a function yourself, SQL Server has the RAND function build in already.
https://learn.microsoft.com/en-us/sql/t-sql/functions/rand-transact-sql
Upvotes: 0