CODEWITHSUNDEEP
pythonpython-3.x
Sagar Devkota
Sagar Devkota

Reputation: 1315

How to accept user input in multi dimension list in Python?

I need to place user input in a multi dimension list in python. I am new at Python. Some user inputs would be

11001111
10001100
11000000

I need to place them in list

a[[1,1,0,0,1,1,1,1],[1,0,0,0,1,1,0,0],[1,1,0,0,0,0,0,0]]

What I do. And its completely useless

for i in range(3):
    for b in range(7):
        a[i][b] = int(input())

Upvotes: 0

Views: 841

Answers (4)

PRMoureu
PRMoureu

Reputation: 13317

This could work too :

a = []
for x in range(3):
    a.append([int(let) for let in input('enter number:\n')])

Upvotes: 0

Jean-François Fabre
Jean-François Fabre

Reputation: 140168

If you accept that the users types 21 digits+enter each time, what you're doing works, although it isn't the best way, looks a lot like C code.

However, it's not useless, it works provided you initialize your bidimensional array properly for instance like this:

a = [[0]*7 for _ in range(3)]

this creates 3 lists of 7 elements. You can read/write them with this exact loop you posted.

If you want to read 3 lines of single digit numbers, you could do it in only like using double list comprehension:

a = [[int(x) for x in input()] for _ in range(3) ]

Upvotes: 1

Akshay Apte
Akshay Apte

Reputation: 1653

Try doing this:

a = []
for i in range(3):
    k = raw_input()
    a.append([int(j) for j in k])

print a

Upvotes: 0

John Zwinck
John Zwinck

Reputation: 249123

You can either read a line at a time and process individual characters:

for i in range(3):
    line = input()
    for b in range(7):
        a[i][b] = int(line[b])

Or you can read a character at a time:

sys.stdin.read(1)

Upvotes: 3

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