hihihihi
hihihihi

Reputation: 88

Passing variable value to URL

I want to pass a variable value to an url but the problem is when I first clicked the search button the value doesn't appear and when the second clicked is triggered the variable value is shown. How can i fix this? I think the fault is when i click the search button the page is refreshing. Can someone help me about this?

here's my code:

 <div class="form-inline form-padding">
                    <form action="student.php?classid=<?php echo $classid;?>" method="post">
                        <input type="text" class="form-control" name="search" placeholder="Search by ID or Name">
                        <select name="subject" class="form-control" required>
                            <option value="">Select Subject...</option>                            
                            <?php while($row = mysql_fetch_array($mysubject)): ?>
                                <option value="<?php echo $row['id']?>" <?php if($row['id']==$classid) echo 'selected'; ?>><?php echo $row['subject'];?></option>
                            <?php endwhile; ?>
                        </select>
                        <button type="submit" name="submit" id="submit" class="btn btn-primary"><i class="fa fa-search"></i> Search</button>                       
                        <a href="print.php?classid=<?php echo $classid; ?>" target="_blank"><button type="button" name="submit" class="btn btn-success"><i class="fa fa-print"></i> Print</button></a>            
                    </form>
                </div>

enter image description here

Upvotes: 1

Views: 53

Answers (1)

in your

<form action="student.php?classid=<?php echo $classid;?>" method="post">

change it to

<form action="student.php" method="post">

Upvotes: 1

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