CODEWITHSUNDEEP
arraysbash
Lenik
Lenik

Reputation: 14458

Bash indirect array addressing?

Suppose I have some bash arrays: 

A1=(apple trees)
A2=(building blocks)
A3=(color television)

And index J=2, how to get the array contents of A2?

Upvotes: 27

Views: 4984

Answers (3)

Charles Duffy
Charles Duffy

Reputation: 295472

Today (with bash 4.3 and later), the best practice is to use nameref support:

A1=(apple trees)
A2=(building blocks)
A3=(color television)
J=2

declare -n A="A$J"
printf '%q\n' "${A[@]}"

...will properly emit:

building
blocks

This is also available as nameref A="A$J" on ksh93. See BashFAQ #6 for details.

Upvotes: 5

Reuti
Reuti

Reputation: 211

It’s worth to note, that even an index will be substituted at time the variable is evaluated:

$ A2=(building blocks)
$ Aref=A2[index]
$ index=1
$ echo "${!Aref}"
blocks

Upvotes: 21

Lenik
Lenik

Reputation: 14458

I've already found a resolution, this can be done by: 

$ Aref=A$J
$ echo ${!Aref}
building
$ Aref=A$J[1]
$ echo ${!Aref}
blocks
$ Aref=A$J[@]
$ echo "${!Aref}"
building blocks

Upvotes: 22

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