CODEWITHSUNDEEP
pythonlist
Chas
Chas

Reputation: 159

Trying to compare a list element

In the code below, at if path_parts[-2:-1]=='training' I want my function to step into counting files at that location. My print(path_parts[-2:-1]) demonstrates that the code is finding the 'training' folder I'm looking for but the evaluation doesn't prove 'true'.

What am I doing wrong?

for dirs_name, sub_dirs, files in os.walk(file_path):
    count=0
    name=''
    if os.path.basename(dirs_name)== '2016':
        path_parts = [x.lower() for x in dirs_name.split('\\')]
        print(path_parts[-2:-1])
        if path_parts[-2:-1] == 'training':
            'statement'

Output of the print statement       
['training']
['training']
['training']
['training']

Upvotes: 1

Views: 53

Answers (2)

MSeifert
MSeifert

Reputation: 152820

Your path_parts[-2:-1] returns a list (because you slice the list) and you then compare it with a string 'training'. That's always False because these lists and strings are incomparable.

But you can simply access the second-last item with path_parts[-2]:

if path_parts[-2] == 'training':

Upvotes: 3

khelwood
khelwood

Reputation: 59232

As you can see from your output, path_parts[-2:-1] is ['training']. That's a list. But you're comparing it to 'training', which is a string.

You mean:

# Is this sublist equal to a list containing the string 'training'?
if path_parts[-2:-1] == ['training']:

or more simply:

# Is the element at position -2 equal to the string 'training'?
if path_parts[-2] == 'training':

Upvotes: 3

Related Questions