CODEWITHSUNDEEP
scalagraphqlsangria
user8504370
user8504370

Reputation: 21

What is a proper signature of Executor.execute(​????) in Sangria middleware to log slow GraphQL queries?

I am trying to integrate Sangria middleware to log slow GraphQL queries in my application but getting the following compilation

Error:

type mismatch;
found : sangria.schema.Schema[models.UserRepo,Unit]
required: sangria.schema.Schema[Any,Unit]
Note:models.UserRepo <:Any,but class Schema is invariant in type
Ctx.
You may wish to define Ctx as +Ctx instead. (SLS 4.5)
Error occurred in an application involving default arguments.

Code snippet:

val Query = ObjectType("Query", List[Field[UserRepo, Unit]]
(Field("store", StoreType, resolve = _ ⇒ ()) ))

val schema = Schema(Query, Some(MutationType))

val logResult = Executor.execute(SchemaDefinition.schema,
  query.asInstanceOf[Document], middleware = SlowLog(newlogger,
  threshold = 10 seconds) :: Nil)

Here is the reference link: https://github.com/sangria-graphql/sangria-slowlog

Kindly help me to know what is a proper signature of Executor.execute(​​​????)

Thanks!

Upvotes: 2

Views: 418

Answers (1)

tenshi
tenshi

Reputation: 26586

I think the main issue is that you've defined the schema in terms of UserRepo, but you haven't provided it at the execution time. I guess adding a userContext argument should fix the issue:

Executor.execute(SchemaDefinition.schema, query,
  userContext = new UserRepo,
  middleware = SlowLog(newlogger, threshold = 10 seconds) :: Nil)

I also made this test to check the types (these types are similar to your scenario), but it compiles just fine:

val schema: Schema[Repo, Unit] = ???
val md: Middleware[Any] = ???

Executor.execute(schema, query, new Repo, middleware = md :: Nil)

If it still does not compile, I would suggest you to provide complete self-contains example that reproduces the issue. (for instance, in your example you don't show the type of MutationType)

Upvotes: 2

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