Reputation: 57
I have found that we could sort a column in table even if it is alpha numeric.
The only problem here I have is if the column data is only characters it throws error.
BEGIN TRAN
USE SomeDatabase
CREATE TABLE dbo.Section
(
Section varchar(50) NULL
)
INSERT INTO dbo.Section (Section.Section) VALUES ('BB')
INSERT INTO dbo.Section (Section.Section) VALUES ('1 ')
INSERT INTO dbo.Section (Section.Section) VALUES ('AB 1')
INSERT INTO dbo.Section (Section.Section) VALUES ('A21')
INSERT INTO dbo.Section (Section.Section) VALUES ('B2')
INSERT INTO dbo.Section (Section.Section) VALUES ('A11')
INSERT INTO dbo.Section (Section.Section) VALUES ('B20')
INSERT INTO dbo.Section (Section.Section) VALUES ('B21')
INSERT INTO dbo.Section (Section.Section) VALUES ('AB10')
INSERT INTO dbo.Section (Section.Section) VALUES ('A10')
SELECT Section
FROM dbo.Section
SELECT Section
FROM dbo.Section
ORDER BY LEFT(Section,PATINDEX('%[0-9]%',Section)-1), -- alphabetical sort
CONVERT(INT,SUBSTRING(Section,PATINDEX('%[0-9]%',Section),LEN(Section))) -- numerical sort
DROP Table dbo.Section
ROLLBACK
So, sorting 'BB' is the problem. If you remove BB then it all works just fine.
Upvotes: 3
Views: 79
Reputation: 555
The obvious problem from looking at your code, is that the PATINDEX
will return 0 if it doesn't find anything. Because you then have 0 - 1
as a length, the LEFT function will throw an error.
Try this instead:
...
ORDER BY LEFT(Section
,CASE WHEN PATINDEX('%[0-9]%',Section) >= 2
THEN PATINDEX('%[0-9]%',Section) - 1
ELSE LEN(Section)
END
), -- alphabetical sort
CASE WHEN PATINDEX('%[0-9]%',Section) >= 1
THEN CONVERT(INT,SUBSTRING(Section,PATINDEX('%[0-9]%',Section),LEN(Section) - PATINDEX('%[0-9]%',Section) - 1))
END -- numerical sort
...
Upvotes: 1
Reputation: 38033
You can use stuff()
instead of substring()
like so:
select section
, alpha = left(section,patindex('%[0-9]%',section+'0')-1)
, num = stuff(section,1,patindex('%[0-9]%',section)-1,'')
from section
order by
left(section,patindex('%[0-9]%',section+'0')-1)
, convert(int,stuff(section,1,patindex('%[0-9]%',section)-1,''))
rextester demo: http://rextester.com/JOXUEE9700
output:
+---------+-------+------+
| section | alpha | num |
+---------+-------+------+
| 1 | | 1 |
| A10 | A | 10 |
| A11 | A | 11 |
| A21 | A | 21 |
| AB 1 | AB | 1 |
| AB10 | AB | 10 |
| B2 | B | 2 |
| B20 | B | 20 |
| B21 | B | 21 |
| BB | BB | NULL |
+---------+-------+------+
Upvotes: 1
Reputation: 1080
The problem is the Patindex is returning 0 in both order by clause. I corrected it below.
declare @Section TABLE
(
Section varchar(50) NULL
)
INSERT INTO @Section (Section) VALUES ('BB')
INSERT INTO @Section (Section) VALUES ('1 ')
INSERT INTO @Section (Section) VALUES ('AB 1')
INSERT INTO @Section (Section) VALUES ('A21')
INSERT INTO @Section (Section) VALUES ('B2')
INSERT INTO @Section (Section) VALUES ('A11')
INSERT INTO @Section (Section) VALUES ('B20')
INSERT INTO @Section (Section) VALUES ('B21')
INSERT INTO @Section (Section) VALUES ('AB10')
INSERT INTO @Section (Section) VALUES ('A10')
SELECT Section
FROM @Section
SELECT Section
FROM @Section
ORDER BY Section
--LEFT(Section,PATINDEX('%[0-9]%',Section)-1), -- alphabetical sort
-- CONVERT(INT,SUBSTRING(Section,PATINDEX('%[0-9]%',Section),LEN(Section))) -- numerical sort
SELECT Section
FROM @Section
ORDER BY LEFT(Section,case when PATINDEX('%[0-9]%',Section) < 1 then 1 else PATINDEX('%[0-9]%',Section) end -1), -- alphabetical sort
case when PATINDEX('%[0-9]%',Section) < 1 then 0 else CONVERT(INT,SUBSTRING(Section,PATINDEX('%[0-9]%',Section),LEN(Section))) end -- numerical sort
Section
--------------------------------------------------
BB
1
AB 1
A21
B2
A11
B20
B21
AB10
A10
Section
--------------------------------------------------
BB
1
A10
A11
A21
AB 1
AB10
B2
B20
B21
Upvotes: 1