Reputation: 85
Consider the following two groups of code:
random (mkStdGen 1) :: (Int, StdGen)
-- returns (7918028818325808681,545291967 2103410263)
random (mkStdGen 1) :: (Bool, StdGen)
-- returns (True,80028 40692)
random (mkStdGen 949488) :: (Int, StdGen)
-- returns (9159618695640234475,587416689 2103410263)
random (mkStdGen 949488) :: (Bool, StdGen)
-- returns (False,1485632275 40692)
Why does 7918028818325808681
translate to True
but 9159618695640234475
translates to False
?
Upvotes: 1
Views: 114
Reputation: 25782
The Instance Bool
shares the implementation with Instance Int
, but the code that is shared is the one for randomR
, which takes a range. We can verify this using QuickCheck:
Prelude> import Test.QuickCheck
Prelude Test.QuickCheck> import System.Random
Prelude Test.QuickCheck System.Random> :{
Prelude Test.QuickCheck System.Random| prop seed = let
Prelude Test.QuickCheck System.Random| gen = mkStdGen seed
Prelude Test.QuickCheck System.Random| b = fst (random gen)
Prelude Test.QuickCheck System.Random| i = fst (randomR (0,1) gen)
Prelude Test.QuickCheck System.Random| in if b then i == 1 else i == 0
Prelude Test.QuickCheck System.Random| :}
Prelude Test.QuickCheck System.Random> quickCheck prop
+++ OK, passed 100 tests.
You can also look at the definition of the instance Random Bool
where you will find this code:
instance Random Bool where
randomR (a,b) g =
case (randomIvalInteger (bool2Int a, bool2Int b) g) of
(x, g') -> (int2Bool x, g')
where
bool2Int :: Bool -> Integer
bool2Int False = 0
bool2Int True = 1
int2Bool :: Int -> Bool
int2Bool 0 = False
int2Bool _ = True
random g = randomR (minBound,maxBound) g
so essential, you are calling randomR (0,1)
and then mapping 0
to False
and 1
to True
:
> random (mkStdGen 949488) :: (Bool, StdGen)
(False,1485632275 40692)
> randomR (0,1) (mkStdGen 949488) :: (Int, StdGen)
(0,1485632275 40692)
> random (mkStdGen 1) :: (Bool, StdGen)
(True,80028 40692)
> randomR (0,1) (mkStdGen 1) :: (Int, StdGen)
(1,80028 40692)
Upvotes: 8