CODEWITHSUNDEEP
pythondictionary
Chris Lin
Chris Lin

Reputation: 25

Create a new dict of first n values (and keys) from dictionary - Python

I have a dictionary:

{'my_account': [45010045, 43527907, 45147474, 35108100, 45159973],
 'your_account': [38966628, 28171579, 39573751, 41359842, 42445236],
 'his_account': [44822460, 45010045, 39276850, 39896128, 45265335]
}

I want to keep the first 2 elements of every key, so the result would look like:

{'my_account': [45010045, 43527907],
 'your_account': [38966628, 28171579],
 'his_account': [44822460, 45010045]
}

Is there any way to achieve this? Thanks.

Upvotes: 1

Views: 832

Answers (2)

Skycc
Skycc

Reputation: 3555

using dictionary comprehension

my_dict = {'my_account': [45010045, 43527907, 45147474, 35108100, 45159973],
 'your_account': [38966628, 28171579, 39573751, 41359842, 42445236],
 'his_account': [44822460, 45010045, 39276850, 39896128, 45265335]
}

new_dict = {k:v[:2] for k,v in my_dict.items()}
# {'my_account': [45010045, 43527907], 'your_account': [38966628, 28171579], 'his_account': [44822460, 45010045]}

Upvotes: 2

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 799110

Just slice-delete the values.

for v in D.itervalues():
  del v[2:]

Upvotes: 0

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