CODEWITHSUNDEEP
javascriptregexhashtag
user7308733
user7308733

Reputation:

Extract all hashtags from string without #

I'm extracting hashtags from strings like this:

const mystring = 'huehue #arebaba,saas #ole #cool asdsad #aaa';
const hashtags = mystring.match(/#\w+/g) || [];
console.log(hashtags);

The output is:

['#arebaba', '#ole', '#cool', '#aaa']

How my regex should be so that the match is:

['arebaba', 'ole', 'cool', 'aaa']

I don't want to use map function!

Upvotes: 3

Views: 1857

Answers (3)

Diego Mc
Diego Mc

Reputation: 5

You can use the Positive Lookbehind option:

(?<=...) Ensures that the given pattern will match, ending at the current position in the expression. The pattern must have a fixed width. Does not consume any characters.

For example given the string 'foobar', the regex (?<=foo)bar would match bar only.

Or in this case (crating an array of word tags):

const mystring = 'huehue #arebaba,saas #ole #cool asdsad #aaa';
const hashtags = mystring.match(/(?<=#)\w+/g) || [];
// ["arebaba","ole","cool","aaa"];

Upvotes: 0

Marc Lambrichs
Marc Lambrichs

Reputation: 2882

const mystring = 'huehue #arebaba,saas #ole #cool asdsad #aaa';
var regexp = /#(\w+)/g;
var match = regexp.exec(mystring);
while (match != null){
  console.log(match[1])
  match = regexp.exec(mystring)
}

EDIT The code can be shortened. However, it's not your regex that will solve your problem, but picking the correct method.

var mystring = 'huehue #arebaba,saas #ole #cool asdsad #aaa',
    match;
var regexp = /#(\w+)/g;    
while (match = regexp.exec(mystring))
  console.log(match[1]);

Upvotes: 6

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626738

You already matched multiple substrings and you know there is # in front, so just remove it:

const mystring = 'huehue #arebaba,saas #ole #cool asdsad #aaa';
const hashtags = mystring.match(/#\w+/g).map(x => x.substr(1)) || [];
console.log(hashtags);

Upvotes: 2

Related Questions