CODEWITHSUNDEEP
batch-file
user69453
user69453

Reputation: 1405

How to get major, minor, etc. version number of a program in batch file?

A program returns a version string of this regex type [0-9]{1,}\.[0-9]{1,}\.[0-9]{1,}\.[0-9]{1,} on the command line. Therefore the output looks like this:

C:\users\user\desktop>a.exe --version
Version: 1.22.53.4134

I save the output to a variable Version by this get-version-info.bat

for /f "usebackq tokens=1* delims=: " %%i in (`a.exe --version`) do (
    if /i "%%i"=="Version" set "Version=%%j"
)

To solve my exact problem I only need the major and minor release number(s), but a general, adaptable solution would be also good of course.

How to get major and minor version number of the program in batch file?

Upvotes: 1

Views: 496

Answers (2)

Mofi
Mofi

Reputation: 49096

You can use this single command line in your batch file:

for /F "tokens=1-3 delims=:. " %%I in ('a.exe --version') do if /I "%%I" == "Version" set "Version=%%J.%%K"

The delimiters for splitting up the line output by a.exe are colon :, point . and space   as specified with delims=:. .

Of interest are only the first 3 substrings (tokens) as specified with tokens=1-3. The first substring being Version is assigned to specified loop variable I. The second substring being 1 is assigned to next loop variable according to ASCII table which is J. and the third substring being 22 is assigned to loop variable K.

Upvotes: 1

user6811411
user6811411

Reputation:

Add the dot to the delims, extend the tokens and compound your Ver with the wanted elements:

for /f "usebackq tokens=1-4* delims=:. " %%i in (`a.exe --version`) do (
  if /i "%%i"=="Version" set "VerMAjorMinor=%%j.%%k"
)

Upvotes: 1

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