CODEWITHSUNDEEP
pythonsorting
HighwayJohn
HighwayJohn

Reputation: 921

Sorting a nested string list for the second element (python)

I have the following problem. I have a nested list which contains football scores and their odds like it is shown in this short example.

scoreresultlist = [('1:0', '23.00'), ('0:0', '12.50'), ('0:1', '10.00'),('2:0', '36.00'), 
                  ('1:1', '9.50')]

Now I would like to sort the scores according to their odds. My problem is, that it is a nested list and all entries are saved as strings. Hope you can help and thanks in advance!

Upvotes: 0

Views: 1075

Answers (1)

Zachary Espiritu
Zachary Espiritu

Reputation: 987

What you're really asking is to sort an array of tuples by their second element, which you can do by:

sorted_list = sorted(scoreresultlist, key=lambda element: Decimal(element[1]))

If you want to sort it in place, you can do

scoreresultlist.sort(key=lambda element: Decimal(element[1]))

(The Decimal(element[1])) type casts the string element to a Decimal for sorting purposes but does not modify the list.)

Upvotes: 1

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