CODEWITHSUNDEEP
pythonfor-loopiteration
Soros
Soros

Reputation: 41

How to iterate over multiple related lists until specified number times in python?

I want to iterate to Nth times my list. This is my example code.

a = [2, 4, 6, 8, 10]
b = [i - 1 for i in a]
print(b)
c = [i * 10 for i in b]
print(c)
d = [i / 3 for i in c]
print(d)
a = [m/n for m,n in zip(d,a)]
print(a)
b=[i - 1 for i in a]
print(b)
c = [i * 10 for i in b]
print(c)
d = [i / 3 for i in c]
print(d)
a = [m/n for m,n in zip(d,a)]
print(a)

For example, I want to do iteration 10 times over all the lists. But I don't want to write those same codes 10 times. Is there efficient way to get my desired results? Thanks in advance.

Upvotes: 0

Views: 60

Answers (3)

Denis Osipov
Denis Osipov

Reputation: 91

Maybe you should use something like this

def lists_iteration(a,n):
    for k in range(n):
        b = [i - 1 for i in a]
        print(b)
        c = [i * 10 for i in b]
        print(c)
        d = [i / 3 for i in c]
        print(d)
        a = [m/n for m,n in zip(d,a)]
        print(a)

or just for loop from this function.

Upvotes: 2

Moses Koledoye
Moses Koledoye

Reputation: 78554

If you don't actually need the intermediate lists, you can combine all the maths ops into one:

def func(a, n):
   for _ in range(n):
      a = [(i-1)*10/(3*i) for i in a]
   return a

Upvotes: 2

Kallz
Kallz

Reputation: 3523

>>> a = [2, 4, 6, 8, 10]
>>> x = [(i-1,(i-1)*10,((i-1)*10)/3) for i in a]
>>> print x 
[(1, 10, 3), (3, 30, 10), (5, 50, 16), (7, 70, 23), (9, 90, 30)] 
>>>
>>> b = [i[0] for i in x ]
>>> print b
[1, 3, 5, 7, 9]
>>> c = [i[1] for i in x]
>>> print c
[10, 30, 50, 70, 90]
>>> d = [i[2] for i in x]
>>> print d 
[3, 10, 16, 23, 30]

Upvotes: 0

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