CODEWITHSUNDEEP
jenkinsgroovyjenkins-pipeline
Karthi
Karthi

Reputation: 585

How to do regex validation in Jenkins pipeline file?

I tried to execute the shell commands and store the output result content to the string variable. From that string variable, i need to find and get whether the required decimal value using regular expression. Below is the code i tried. Job got failed continuously. Could anyone please help me to resolve this?

My output should be like "5.2.0".

node("10.6")
{
stage 'test' 
try
{   
def matcher = "5.2.0.123" =~ /^[0-9]+(\.[0-9]+)?(\.[0-9]+)?/
if( matcher.matches() ) { echo "success"} 
}
catch(Exception e)
{ echo e
}

}

Upvotes: 0

Views: 6680

Answers (1)

fsi
fsi

Reputation: 1367

In your statement true, use findAll method to return the output from regex, like this:

​"5.2.0.123".findAll(/^[0-9]+(\.[0-9]+)?(\.[0-9]+)?/)[0]​

Upvotes: 1

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