Reputation: 755
I have a list of customer whose name is given as a full name. I want to create a function that takes the full name as parameter and returns the first and last name separately. If this is not possible I can have two separate functions one that returns the first name and the other that returns the last name. The full name list contains names that have a maximum of three words. What I want is this:-
Example:-
**Full Name**
John Paul White
Peter Smith
Ann Marie Brown
Jack Black
Sam Olaf Turner
Result:-
**First Name Last Name**
John Paul White
Peter Smith
Ann Marie Brown
Jack Black
Sam Olaf Turner
I have search and found solutions that are not working as intended and would like some advice.
Upvotes: 3
Views: 16800
Reputation: 1
What worked for me was the following:
SUBSTR(Full_Name,1,(LOCATE(Full_Name, ' '))) AS FIRSTTNAME,
SUBSTR(Full_Name,(LOCATE(Full_Name, ' ')+1)) AS LASTNAME
Upvotes: 0
Reputation: 2817
You can try the below query. It is written as per your requirement and it only handles full_name with 2 or 3 parts in it.
;WITH cte AS(
SELECT full_name, (LEN(full_name) - LEN(REPLACE(full_name, ' ', '')) + 1) AS size FROM @temp
)
SELECT FirstName =
CASE
WHEN size=3 THEN PARSENAME(REPLACE(full_name, ' ', '.'), 3) + ' ' + PARSENAME(REPLACE(full_name, ' ', '.'), 2)
ELSE PARSENAME(REPLACE(full_name, ' ', '.'), 2)
END,
PARSENAME(REPLACE(full_name, ' ', '.'), 1) AS LastName
FROM cte
Upvotes: 0
Reputation: 44336
Keeping it short and simple
DECLARE @t TABLE(Fullname varchar(40))
INSERT @t VALUES('John Paul White'),('Peter Smith'),('Thomas')
SELECT
LEFT(Fullname, LEN(Fullname) - CHARINDEX(' ', REVERSE(FullName))) FirstName,
STUFF(RIGHT(FullName, CHARINDEX(' ', REVERSE(FullName))),1,1,'') LastName
FROM
@t
Result:
FirstName LastName
John Paul White
Peter Smith
Thomas NULL
Upvotes: 7
Reputation: 82010
Another option (just for fun) is to use a little XML in concert with an CROSS APPLY
Example
Select FirstName = ltrim(reverse(concat(Pos2,' ',Pos3,' ',Pos4,' ',Pos5)))
,LastName = reverse(Pos1)
From YourTable A
Cross Apply (
Select Pos1 = xDim.value('/x[1]','varchar(max)')
,Pos2 = xDim.value('/x[2]','varchar(max)')
,Pos3 = xDim.value('/x[3]','varchar(max)')
,Pos4 = xDim.value('/x[4]','varchar(max)')
,Pos5 = xDim.value('/x[5]','varchar(max)')
From (Select Cast('<x>' + replace(reverse(A.[Full Name]),' ','</x><x>')+'</x>' as xml) as xDim) XMLData
) B
Returns
FirstName LastName
John Paul White
Peter Smith
Ann Marie Brown
Jack Black
Sam Olaf Turner
Cher
Sally Anne Bella Donna Baxter
Upvotes: 1
Reputation: 3514
Make it a table-valued function.
see here for an example
And this is the code you need to create your function. Basically you just need to split your LastName
IF OBJECT_ID(N'dbo.ufnParseName', N'TF') IS NOT NULL
DROP FUNCTION dbo.ufnParseName;
GO
CREATE FUNCTION dbo.ufnParseName(@FullName VARCHAR(300))
RETURNS @retParseName TABLE
(
-- Columns returned by the function
FirstName nvarchar(150) NULL,
LastName nvarchar(50) NULL
)
AS
-- Returns the spliced last name.
BEGIN
DECLARE
@FirstName nvarchar(250),
@LastName nvarchar(250);
-- Get common contact information
SELECT @LastName = RTRIM(RIGHT(@FullName, CHARINDEX(' ', REVERSE(@FullName)) - 1));
SELECT @FirstName = LTRIM(RTRIM(Replace(@FullName, @LastName, '')))
INSERT @retParseName
SELECT @FirstName, @LastName;
RETURN;
END
You can run as SELECT * FROM dbo.ufnParseName('M J K');
You can get rid off the duplication of your sql query and achieve DRY
Upvotes: 0
Reputation: 1231
Have you tried by Using PARSENAME Function?
The last method in splitting a full name into its corresponding first name and last name is the use of the PARSENAME string function, as can be seen from the following script:
DECLARE @FullName VARCHAR(100)
SET @FullName = 'John White Doe'
SELECT CONCAT(PARSENAME(REPLACE(@FullName, ' ', '.'), 3),' ',PARSENAME(REPLACE(@FullName, ' ', '.'), 2)) AS [FirstName],
PARSENAME(REPLACE(@FullName, ' ', '.'), 1) AS [LastName]
For more information, Goto this Site
This is the output..
Upvotes: 0
Reputation: 522636
If you are certain that your names will only ever be two or three words, with single spaces, then we can rely on the base string functions to extract the first and last name components.
SELECT
CASE WHEN LEN(col) = LEN(REPLACE(col, ' ', '')) + 2
THEN SUBSTRING(col, 1,
CHARINDEX(' ', col, CHARINDEX(' ', col) + 1) - 1)
ELSE SUBSTRING(col, 1, CHARINDEX(' ', col) - 1)
END AS first,
CASE WHEN LEN(col) = LEN(REPLACE(col, ' ', '')) + 2
THEN SUBSTRING(col,
CHARINDEX(' ', col, CHARINDEX(' ', col) + 1) + 1,
LEN(col) - CHARINDEX(' ', col, CHARINDEX(' ', col)))
ELSE SUBSTRING(col,
CHARINDEX(' ', col) + 1,
LEN(col) - CHARINDEX(' ', col))
END AS last
FROM yourTable;
Yuck, but it seems to work. My feeling is that you should fix your data model at some point. A more ideal place to scrub your name data would be outside the database, e.g. in Java. Or, better yet, fix the source of your data such that you record proper first and last names from the very beginning.
Demo here:
Upvotes: 1
Reputation: 1095
You're trying to do two things at once...I won't solve for you, but here's the direction I'd take:
1) Check this out for string splitting: https://ole.michelsen.dk/blog/split-string-to-table-using-transact-sql.html. This will allow you to parse the name into a temp table and you can perform your logic on it to create names based on your rules
2) Create this as a table-valued function so that you can return a single row of parsed FirstName, LastName from your parameter. That way you can join to it and include in your results
Upvotes: 0