CODEWITHSUNDEEP
datetimerust
user1916077
user1916077

Reputation: 451

BadFormat parsing string to date when using Chrono

I am trying to convert a string to a date using the Chrono library. I always get a BadFormat or NotEnough error:

extern crate chrono;

use chrono::prelude::*;

fn main() {
    let dt1 = DateTime::parse_from_str(
        "2017-08-30 18:34:06.638997932 UTC", 
        "%Y-%m-%d %H:%M:%S.%9f"
    );
    println!("{:?}", dt1);
}

I'm not sure what I am doing wrong.

Upvotes: 0

Views: 1010

Answers (1)

Shepmaster
Shepmaster

Reputation: 432039

  1. As mentioned in the comments, your format string doesn't allow for the " UTC" part of your string. That's why you get the BadFormat error.

  2. If you add " UTC" to your format string, you still get a BadFormat error because you've typed .%9f when it should be %.9f.

  3. Once you fix that, you get a NotEnough error because we aren't actually parsing a timezone.

I'd use NaiveDateTime to always parse in UTC and then add the " UTC" onto the format string to ignore it, correcting the typo:

use chrono::prelude::*; // 0.4.9

fn main() {
    let dt1 = NaiveDateTime::parse_from_str(
        "2017-08-30 18:34:06.638997932 UTC",
        "%Y-%m-%d %H:%M:%S%.9f UTC",
    );

    println!("{:?}", dt1); // Ok(2017-08-30T18:34:06.638997932)
}

Upvotes: 2

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