CODEWITHSUNDEEP
phpheidisql
notsoeasy
notsoeasy

Reputation: 61

foreach loop in database table column with multiple images

<?php  
    $images= $uploading['front_image'];
    $whileimg= explode(",", $images);
    foreach ($whileimg as $key => $image) {
        echo  $uploading["front_image"];          
    }
?>

In database I have my images saved in one column(2,3,4 it depends). now when I want them all to show in web ,Instead of images I get the path of the photos, as are saved in database. thank you

Upvotes: 0

Views: 1752

Answers (3)

Deepansh Sachdeva
Deepansh Sachdeva

Reputation: 1198

Assuming you are fetching comma separated paths of images using the following line:

$images= $uploading['front_image'];

You just need to use the following loop after creating array of paths:

foreach ($whileimg as $key => $image) {
    echo "<img src='$image'>";
}

Upvotes: 0

clearshot66
clearshot66

Reputation: 2302

You need to make it an image take and echo the path in the img is what it sounds like you're getting:

 echo "<img src='".$image."' />

instead of

echo  $uploading["front_image"];

So:

<?php  
    $images= $uploading['front_image'];
    $whileimg= explode(",", $images);
    foreach ($whileimg as $key => $image) {
        echo "<img src='".$image."' />          
    }
?>

Upvotes: 1

Ravinder Reddy
Ravinder Reddy

Reputation: 3879

To display images, you have use img tag

foreach ($whileimg as $key => $image) {
        echo  "<img src='".$image."' alt='image'>";   
    }

Upvotes: 1

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