CODEWITHSUNDEEP
c#
DarthVegan
DarthVegan

Reputation: 1269

The variable is not of a kind that is allowed in the group C#

I'm trying to get my code to match what the following code does:

var data = new Dictionary<string, object>() {
                    { "state", new string[] { "Ohio", "Ohio", "Ohio", "Nevada", "Nevada" } },
                    { "year", new int[] { 2000, 2001, 2002, 2001, 2002 } },
                    { "pop", new double[] { 1.5, 1.7, 3.6, 2.4, 2.9 } }
                };

My current code:

var data = new Dictionary<string, object>() {
                            { "targetValue", calc.ListCalculationData.Select(i => i.MRTargetValue).ToArray<decimal>() },
                            { "ema12", calc.ListCalculationData.Select(i => i.Ema12).ToArray<decimal>() },
                            { "ema26", calc.ListCalculationData.Select(i => i.Ema26).ToArray<decimal>() },
                            { "ema", calc.ListCalculationData.Select(i => i.Ema).ToArray<decimal>() }
                            };

var df1 = DataFrame.FromColumns(data);
var model2 = new LinearRegressionModel(df1, "targetValue ~ ema12 + ema26 + ema"); <= This line gives me the error

I'm getting the following error from the api that I'm using which is the extreme optimization C# api and here is the reference url: http://www.extremeoptimization.com/QuickStart/CSharp/DataFrames.aspx

The variable is not of a kind that is allowed in the group.

Upvotes: 1

Views: 104

Answers (1)

Poosh
Poosh

Reputation: 542

I do not see any documentation or examples using the decimal type, but I cannot verify since I do not have access to the library.

There were some examples using the double type. If precision of 15-16 digits is acceptable, that could be an option. Try defining your data variable like this, casting to a double in the Select, then converting to an array:

var data = new Dictionary<string, object>() {
                            { "targetValue", calc.ListCalculationData.Select(i => (double)i.MRTargetValue).ToArray() },
                            { "ema12", calc.ListCalculationData.Select(i => (double)i.Ema12).ToArray() },
                            { "ema26", calc.ListCalculationData.Select(i => (double)i.Ema26).ToArray() },
                            { "ema", calc.ListCalculationData.Select(i => (double)i.Ema).ToArray() }
                            };

Upvotes: 2

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