CODEWITHSUNDEEP
clinuxgccsegmentation-faultcodeblocks
bigcoder
bigcoder

Reputation: 21

random segmentation fault without any illegal access

When I compile and run the following code using terminal commands(in linux mint sonya)

gcc -o program program.c ./program

I get a segmentation fault. When I do the same using Code::blocks IDE, I don't get any error. I am aware that segmentation fault arises when an illegal memory is accessed. What's wrong?

 #include <stdio.h>
    int main()
    {
    int t;
    scanf("%d",&t);
    for(t;t>0;t--)
        {
        int i,j,n,arr[n],sump=0,sums=0,total,ans;
        scanf("%d",&n);
        for(i=0;i<=n-1;i++) scanf("%d",&arr[i]);
        for(i=0;i<=n-1;i++,sump=0,sums=0)
                {
            for(j=0;j<=i;j++) sump=sump+arr[j];
            for(j=n-1;j>=i;j--) sums=sums+arr[j];
            if(i==0) ans=sump+sums;
            else if(ans>sump+sums) ans=sump+sums;
                }
        for(i=0;i<n;i++,sump=0,sums=0)
            {
            for(j=0;j<=i;j++) sump=sump+arr[j];
            for(j=n-1;j>=i;j--) sums=sums+arr[j];
                if(ans==sums+sump) break;
            }
        printf("%d\n",i+1);
        }

    }

Upvotes: 0

Views: 175

Answers (1)

Leonardo Alves Machado
Leonardo Alves Machado

Reputation: 2837

You are declaring arr[n] without initializing the value of n. That is undefined behavior...

Upvotes: 7

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