CODEWITHSUNDEEP
laravellaravel-5guzzle
Info E
Info E

Reputation: 147

Handling Client Errors exceptions on GuzzleHttp

im trying to handdle request status code, basically checking if the status is 200, in case that it isnt handle it. Im using a package called "GuzzleHttp\Client", when there is a 404 it gives me a error:

Client error: `GET https://api.someurl---` resulted in a `404 Not Found` response:
{"generated_at":"2017-09-01T16:59:25+00:00","schema":"","message":"No events scheduled for this date."}

But than in the screen is displayed in a format that i want to change, so im trying to catch and give a different output on the view. But is not working, it stills gives me the red screen error.

try {
            $client = new \GuzzleHttp\Client();
            $request = $client->request('GET', $url);
            $status = $request->getStatusCode();
            if($status == 200){
                return $status;

            }else{

                throw new \Exception('Failed');
            }

        } catch (\GuzzleHttp\Exception\ConnectException $e) {
            //Catch errors
            return $e->getStatusCode();

        }

Upvotes: 5

Views: 9131

Answers (1)

JLeggatt
JLeggatt

Reputation: 231

Okay so if you want to stick with a try-catch you want to do something like this:

$client = new \GuzzleHttp\Client();

try {
    $request = $client->request('GET', $url);
} catch (\GuzzleHttp\Exception\ConnectException $e) {
    // This is will catch all connection timeouts
    // Handle accordinly
} catch (\GuzzleHttp\Exception\ClientException $e) {
    // This will catch all 400 level errors.
    return $e->getResponse()->getStatusCode();
}

$status = $request->getStatusCode();

If the catch doesn't get triggered the $request would be successful meaning it'll have a status code of 200. However to to catch the 400 error, ensure you've got http_errors request option is set to true when setting up the $client.

Upvotes: 9

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