CODEWITHSUNDEEP
androidjsoninteger
Peter Alexander Christiaans
Peter Alexander Christiaans

Reputation: 111

Error invalid int when parsing JSONObject into an integer

Basically I want to convert a JSONObject json into an integer (127181078). When I use this code:

int intOfReceivedID = Integer.parseInt(json);

I get this error message:

java.lang.NumberFormatException: Invalid int: 127181078"

When I use this code:

char[] charArray = json.toCharArray();
String stringCharArray = charArray.toString();
testTextView.setText(stringCharArray);

testTextView gives me: [C@2378e625

However, when I use this code:

preprocessedjson = String.valueOf(json);
testTextView.setText(preprocessedjson);

The TextView gives 127181078, but I get the some error when I parse the text to an integer.

  1. Can anybody tell me what going on here?
  2. And could you help me convert my JSONObject into an integer?

This is the php code:

$myfile = fopen($filename, 'r') or die("Unable to open file!");
echo fread($myfile,filesize($filename));
fclose($myfile);

This is the the makeHttpRequest:

JSONObject json = jparser.makeHttpRequest("http://myurl.nl/readspecifictextfile.php","POST",data);

Upvotes: 0

Views: 652

Answers (2)

W.K.S
W.K.S

Reputation: 10095

int intOfReceivedID = Integer.parseInt(json);

I get this error message:

java.lang.NumberFormatException: Invalid int: 127181078"

This happens because there is a new-line character at the end of the ID which can not be parsed into an Integer.

When I use this code:

char[] charArray = json.toCharArray();
String stringCharArray = charArray.toString();
testTextView.setText(stringCharArray);

testTextView gives me: [C@2378e625

By default, calling toString() on an object prints the memory location of the object (in this case [C@2378e625). That's what's being displayed in the TextView.

However, when I use this code:

preprocessedjson = String.valueOf(json);
testTextView.setText(preprocessedjson);

The TextView gives 127181078, but I get the some error when I parse the text to an integer.

You'll get an error when parsing the text to an integer because it still has an invalid new-line character at the end.

If you are receiving a JSONObject from the server which only contains a long, then you can use the getLong() or optLong() methods to retrieve the integer value. The JSON parser automatically handles all the parsing and you don't need to do any additional work.

JSONObject json = jparser.makeHttpRequest("http://myurl.nl/readspecifictextfile.php","POST",data);
final long receivedId = json.optLong();

Upvotes: 0

Deadron
Deadron

Reputation: 5289

This question is confusing but from your error message it looks like this is a Java question that has nothing to do with JSON since your json String in this case looks like it does not in fact contain json(from the exception message).

It looks like the issue is your json value is a number plus additional spaces which Integer.parseInt does not handle.

Try

Integer.parseInt(json.trim())

Upvotes: 2

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