CODEWITHSUNDEEP
pythondjango
Garrett
Garrett

Reputation: 1792

Django: Show link based on model field value

I want the "Admin" link to display based on a field in my UserLevels model called "access_level". If the currently logged in user's access_level field is equal to "admin" then the "Admin" link should display.

Currently there are no errors however the "Admin" link will display for every logged in user and not take into account the access_level field value.

HTML:

{% if user.is_authenticated and userlevels.access_level == 'admin' %}
    <a class="nav-link" href="{% url 'adminpanel:widgets' %}">Admin</a>
{% endif %}

Adminpanel app models.py:

from django.db import models
from django.contrib.auth.models import User

# Create your models here.

    class UserLevels(models.Model):
        user = models.OneToOneField(User)

        access_level = models.CharField(max_length=5,default='user',blank=True)

        def __str__(self):
            return self.user.username

Upvotes: 0

Views: 273

Answers (2)

Mauricio Cortazar
Mauricio Cortazar

Reputation: 4213

should be:

{% if request.user.is_authenticated and request.user.userlevels.access_level == 'admin' %}
    <a class="nav-link" href="{% url 'adminpanel:widgets' %}">Admin</a>
{% endif %}

but is better if you pass that in your view and not in the template

Upvotes: 2

dkarchmer
dkarchmer

Reputation: 5594

userlevel is not valid on its own. It is a property of user, which is set by the fact that you created a oneToOne field.

Try

{% if user.is_authenticated and user.userlevels.access_level == 'admin' %}
   <a class="nav-link" href="{% url 'adminpanel:widgets' %}">Admin</a>
{% endif %}

Upvotes: 1

Related Questions