CODEWITHSUNDEEP
visual-c++
karikari
karikari

Reputation: 6817

How to execute a code after the file is created?

I am having this problem. My ShellExecute works fine, the output is a PNG image file. The problem is this process take some time (seconds) for the file to be produced. Meanwhile, my result here has already executed but it produce error message because the PNG file from ShellExecute does not exist yet. How to make sure that the file is exist first, then after that result can execute. 

    ShellExecute(0,                           
                 _T("open"),            
                 _T("c:\\convert.exe"), 
                 full,                  
                 0,                     
                 SW_HIDE);

    result  = ExecuteExternalProgramCompare(L"c.png", L"t.png");  // this line always gives error because the file c.png is not produce yet by shellexecute above.

update: My attempt to convert to ShellexecuteEx.

SHELLEXECUTEINFO info = {0};

info.cbSize = sizeof(SHELLEXECUTEINFO);
info.fMask  = SEE_MASK_NOCLOSEPROCESS;
info.lpFile = _T("c:\\convert.exe");
info.lpParameters = full;
info.nShow = SW_HIDE;

Upvotes: 0

Views: 245

Answers (1)

Alex
Alex

Reputation: 2013

You should use ShellExecuteEx. This will allow you to get a handle on the called process, so that you can wait for the process to end.

SHELLEXECUTEINFO info = {0};

info.cbSize = sizeof(SHELLEXECUTEINFO);
info.fMask  = SEE_MASK_NOCLOSEPROCESS;
info.lpVerb = _T("open");
info.lpFile = _T("c:\\convert.exe");
info.lpParameters = full;
info.lpDirectory = NULL;
info.nShow = SW_HIDE;

if (ShellExecuteEx (&info))
{
   WaitForSingleObject (info.hProcess, INFINITE);
}

Upvotes: 1

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