CODEWITHSUNDEEP
bash
Andy Bennett
Andy Bennett

Reputation: 1

Script that lists all file names in a folder, along with some text after each name, into a txt file

I need to create a file that lists all the files in a folder into a text file, along with a comma and the number 15 after. For example

My folder has video.mp4, video2.mp4, picture1.jpg, picture2.jpg, picture3.png

I need the text file to read as follows:

video.mp4,15
video2.mp4,15
picture1.jpg,15
picture2.jpg,15
picture3.png,15

No spaces, just filename.ext,15 on each line. I am using a raspberry pi. I am aware that the command ls > filename.txt would put all the file names into a folder, but how would I get a ,15 after every line?

Thanks

Upvotes: 0

Views: 671

Answers (5)

PKo
PKo

Reputation: 978

A solution without a loop:

ls | xargs -i echo {},15 > filename.txt

Upvotes: 0

Mohamed Ali JAMAOUI
Mohamed Ali JAMAOUI

Reputation: 14689

You need to do something like this:

#!/bin/bash
for i in $(ls folder_name); do 
   echo $i",15" >> filename.txt; 
done

It's possible to do this in one line, however, if you want to create a script, consider code readability in the long run.

Edit 1: better solution

As @CristianRamon-Cortes suggested in the comments below, you should not rely on the output of ls because of the problems explained in this discussion: why not parse ls. As such, here's how you should write the script instead:

#!/bin/bash
cd folder_name 
for i in *; do 
   echo $i",15" >> filename.txt; 
done

You can skip the part cd folder_name if you are already in the folder.

Edit 2: Enhanced solution:

As suggested by @kusalananda, you'd better do the redirection after done to avoid opening the file in each iteration of the for loop, so the script will look like this:

#!/bin/bash
cd folder_name 
for i in *; do 
   echo $i",15"; 
done >  filename.txt

Upvotes: 1

Kusalananda
Kusalananda

Reputation: 15633

$ printf '%s,15\n' *
picture1.jpg,15
picture2.jpg,15
picture3.png,15
video.mp4,15
video2.mp4,15

This will work if those are the only files in the directory. The format specifier %s,15\n will be applied to each of printf's arguments (the names in the current directory) and they will be outputted with ,15 appended (and a newline).

If there are other files, then the following would work too, regardless of whether there are files called like this or not:

$ printf '%s,15\n' video.mp4  video2.mp4  picture1.jpg  picture2.jpg  "whatever this is"
video.mp4,15
video2.mp4,15
picture1.jpg,15
picture2.jpg,15
whatever this is,15

Or, on all MP4, PNG and JPEG files:

$ printf '%s,15\n' *.mp4 *.jpg *.png
video.mp4,15
video2.mp4,15
picture1.jpg,15
picture2.jpg,15
picture3.png,15

Then redirect this to a file with printf ...as above... >output.txt.

If you're using Bash, then this will not make use of any external utility, as printf is built into the shell.

Upvotes: 1

RomanPerekhrest
RomanPerekhrest

Reputation: 92874

bash one-liner:

for f in *; do echo "$f,15" >> filename.txt; done

To avoid opening the output file on each iteration you may redirect the entire output with > filename.txt:

for f in *; do echo "$f,15"; done > filename.txt

Upvotes: 2

Quanmao
Quanmao

Reputation: 92

Just 1 command line using 2 msr commands recusively (-r) search specific files:

msr -rp your-dir1,dir2,dirN -l -f "\.(mp4|jpg|png)$" -PAC | msr -t .+ -o '$0,15' -PIC > save-file.txt

  • If you want to sort by time, add --wt to first command like: msr --wt -l -rp your-dirs
  • Sort by size? Add --sz but only the prior one is effective if use both --sz and --wt.
  • If you want to exclude some directory, add like: --nd "^(test|garbage)$"
  • remove tail \r\n in save-file.txt : msr -p save-file.txt -S -t "\s+$" -o "" -R

See msr.exe / msr.gcc48 etc in my open project https://github.com/qualiu/msr tools directory.

Upvotes: 0

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