CODEWITHSUNDEEP
sqloracle-databasegroup-by
user104309
user104309

Reputation: 690

Fetch row which has the maximum value for a column + Minimum value of the same column in the same row

I checked the following questions:

GROUP BY with MAX(DATE)

Fetch the row which has the Max value for a column

Columns : account_number, app_guid, time_event_published(epoch time).

I want the latest row of each app_guid for a given account_number PLUS oldest time_event_published of the same account_number for each app_guid in another column of the latest row.

SELECT id, account_number, app_guid, time_event_published , <oldest_time_event_published_for_2152331553409959696> FROM ( 
  SELECT id, account_number, app_guid, time_event_published,
    RANK() OVER (PARTITION BY app_guid ORDER BY time_event_published DESC) dest_rank
    FROM event where account_number=2152331553409959696
  ) where dest_rank = 1;

I am only able to think of another DB hit with same query with ASC. Is there any other way and how to approach this requirement? 

DB Entries:
2152331553409959696, TEST-ONE-APP_GUID, 25-JAN
2152331553409959696, TEST-ONE-APP_GUID, 1-JAN

2152331553409959696, TEST-TWO-APP_GUID, 25-FEB
2152331553409959696, TEST-TWO-APP_GUID, 1-FEB

Required Result:
2152331553409959696, TEST-ONE-APP_GUID, 25-JAN, 1-JAN
2152331553409959696, TEST-TWO-APP_GUID, 25-FEB, 1-FEB

Upvotes: 0

Views: 426

Answers (2)

Ted at ORCL.Pro
Ted at ORCL.Pro

Reputation: 1612

If I understood your question correctly then I think the below SQL will do what you require:

SELECT id, account_number, app_guid, time_event_published , oldest_time_event_published
FROM ( 
  SELECT id, account_number, app_guid, time_event_published,
    RANK() OVER (PARTITION BY app_guid ORDER BY time_event_published DESC) dest_rank,
    MIN (time_event_published) OVER (PARTITION BY app_guid) oldest_time_event_published
        FROM event where account_number=2152331553409959696
  ) where dest_rank = 1;

Let me know how it works with your data and let us know.

I haven't tested with sample data but I am pretty confident it will work for you!

Ted.

Upvotes: 1

Error_2646
Error_2646

Reputation: 3781

This should work, it's not very attractive though, whether it's better than hitting the table twice depends on performance and readability. 

SELECT  MAX(CASE WHEN dest_rank = 1 THEN id
                 ELSE NULL
             END
           ) AS id,
        MAX(CASE WHEN dest_rank = 1 THEN account_number
                 ELSE NULL
             END
           ) AS account_number,
        app_guid,
        MAX(CASE WHEN dest_rank = 1 THEN time_event_published
                 ELSE NULL
             END
           ) AS time_event_published,
        MAX(CASE WHEN dest_rank_asc = 1 THEN time_event_published
                 ELSE NULL
             END
           ) AS earliest_time_event_published
  FROM (SELECT id, 
               account_number, 
               app_guid, 
               time_event_published,
               RANK() OVER 
                 ( PARTITION BY app_guid 
                        ORDER BY time_event_published DESC
                 ) dest_rank,
               RANK() OVER 
                 ( PARTITION BY app_guid 
                       ORDER BY time_event_published ASC
                 ) dest_rank_asc,
          FROM event 
         WHERE account_number=2152331553409959696
        ) 
 GROUP
    BY app_guid;

Upvotes: 0

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