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c#jsonjson-deserialization
Erik T.
Erik T.

Reputation: 370

Deserialize JSON (Json.NET)

I need a little help with json deserialization. It's the first time I'm using Json, so I have just a little knowledge about it.

I get the following string using a webclient:

[{"name": "somename", "data": [[72, 1504601220], [null, 1504601280], ..., [125, 1504605840]]}]

and tried to serialize it with 

JsonConvert.DeserializeObject<TestObject>(jsonstring)

My class looks like this:

public class TestObject
{
    [JsonProperty(PropertyName = "name")]
    public string TargetName { get; set; }

    [JsonProperty(PropertyName = "data"]
    public List<?????> DataPoints {get; set;}
}

How do I need to design my class to get the data values in some kind of collection so each entry contains the two values inside a bracket?

Thx for your patience and help!

Upvotes: 2

Views: 423

Answers (3)

narekye
narekye

Reputation: 114

There is a some solution for this, C# 7.0 also supports ValueTuple such as this example.

List<(int? ,int?)> DataPoints { get; set; }
// if it not work try this.
List<List<int?>> DataPoints { get; set; }

If your json inner array elements count is equal to 2, so can assume to you use the value tuples.

Assume it is helpful for you.

Upvotes: 0

Ray Krungkaew
Ray Krungkaew

Reputation: 6965

Try this website: http://json2csharp.com/ This website can save a lot of your time if you have just a plain JSON text. It helps you convert it to C# object, although you still have to double check it.

var data = "[{\"name\": \"somename\", \"data\": [[72, 1504601220], [null, 1504601280], [125, 1504605840]]}]";
var obj = JsonConvert.DeserializeObject<List<TestObject>>(data);

public class TestObject
{
    [JsonProperty(PropertyName = "name")]
    public string TargetName { get; set; }
    [JsonProperty(PropertyName = "data")]
    public List<int?[]> DataPoints { get; set; }
}

Upvotes: 2

Jamiec
Jamiec

Reputation: 136074

Your data is a list of arrays containing nullable integers (by the looks of it)

[JsonProperty(PropertyName = "data"]
public List<int?[]> DataPoints {get; set;}

Upvotes: 9

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