CODEWITHSUNDEEP
javascriptjquery
arasif
arasif

Reputation: 336

filter array object using multiple value from array using javascript or jquery

the row users array looks like.

var users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 },{name: 'John',address: 'USA',year:2013 },{name: 'John',address: 'USA',year:2014}];

the filter array is,

var filter_year = ['2010','2011','2012'];

how i can get the result array of filtered using years in filter_year, i need to get result array like.

var users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 }];

Upvotes: 1

Views: 161

Answers (2)

Ankit Shah
Ankit Shah

Reputation: 51

You can use below code to get all users for given years.

var filter_year = ['2010','2011','2012'],
    users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 },{name: 'John',address: 'USA',year:2013 },{name: 'John',address: 'USA',year:2014}],
    filteredUsers = []
    allYears = filter_year.join("|");
    
    for(var user in users) { 
    	if(allYears.indexOf(users[user].year) !== -1) {
      		filteredUsers.push(users[user]);
       }
    }
    
    console.log(filteredUsers);

Upvotes: 1

adeneo
adeneo

Reputation: 318182

Just filter one array based on inclusion in the other array

var users = [{name: 'John',address: 'USA',year:2010 },{name: 'John',address: 'USA',year:2011 },{name: 'John',address: 'USA',year:2012 },{name: 'John',address: 'USA',year:2013 },{name: 'John',address: 'USA',year:2014}];

var filter_year = ['2010','2011','2012'];

var result = users.filter( item => filter_year.includes(item.year+""));

console.log(result)

Note that the years are integers in one array, and strings in the other

Upvotes: 0

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