Reputation: 1022
When I use the following code, it works:
String input = "8:32:03";
String filter = "(\\d{1,2}):(\\d{2})";
Pattern p = Pattern.compile(filter);
Matcher m = p.matcher(input);
if(m.find()) { //Enters the condition.
System.out.println("Found => " + m.group() );
}
However, when I try to take user input as regex it does not work?
String input = "8:32:03";
Scanner reader = new Scanner(System.in);
String filter = reader.nextLine();
Pattern p = Pattern.compile(filter);
Matcher m = p.matcher(input);
if(m.find()) { //Does not enter the condition.
System.out.println("Found => " + m.group() );
}
I tried using Pattern p = Pattern.compile(Pattern.quote(filter));
But that does not work either.
How can I take user input as a valid regex?
Upvotes: 0
Views: 123
Reputation: 27055
I am making an assumption here.. Are you inputting (\\d{1,2}):(\\d{2})
?
If so, the \\
in your example act as escape for the \
.. so for your input to be the same, you would need: (\d{1,2}):(\d{2})
Upvotes: 2