CODEWITHSUNDEEP
javascriptarrayssorting
Jemuel Elimanco
Jemuel Elimanco

Reputation: 556

How to sort two dimentional array with string based on length?

I have two dimentional array and i wan to sort in on order and based on string length. how can i do it? this is my code:

arr = [['ab',0],['ax',0],['ac',0],['bsd',0],['ad',0],['asd',0],['bd',0],['ay',0]];
function sortByLen(a,b){
   return (a[0] < b[0]) ? -1 : 1;
}
arr.sort(sortByLen);
console.log(arr);

i want it to become in this order

["ab", 0]
["ac", 0]
["ad", 0]
["ax", 0]
["ay", 0]
["bd", 0]
["asd", 0]
["bsd", 0]

how can I do it?

Upvotes: 4

Views: 67

Answers (4)

Nina Scholz
Nina Scholz

Reputation: 386654

You might use a single sort with a callback which respects the length of the first item of the inner arrays with using the difference of the length. If the length is equal take String#localeCompare for sorting by alphabet.

var array = [['ab', 0], ['ax', 0], ['ac', 0], ['bsd', 0], ['ad', 0], ['asd', 0], ['bd', 0], ['ay', 0]];

array.sort(function (a, b) {
    return a[0].length - b[0].length || a[0].localeCompare(b[0]);
});

console.log(array);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 1

Alongkorn
Alongkorn

Reputation: 4207

try this

arr = [['ac',0],['ab',0],['ax',0],['bsd',0],['ad',0],['asd',0],['bd',0],['ay',0]];

const sortedItems = arr
  .sort((a, b) => a[0] > b[0])
  .sort((a, b) => a[0].length > b[0].length)

console.log(sortedItems)

Upvotes: 0

Brr Switch
Brr Switch

Reputation: 984

Is this what you are trying to achieve? 

var arr = [['ab',0],['ax',0],['ac',0],['bsd',0],['ad',0],['asd',0],['bd',0],['ay',0]];

var sorted = arr.sort(function(a,b) {
  return a > b
  }).sort(function(a,b) {
     return a[0].length - b[0].length
  })

console.log('sorted',sorted)

Upvotes: 1

ishegg
ishegg

Reputation: 9937

Check if lengths differ. If they do, sort by them. If equal, sort alphabetically:

var arr = [['ab',0],['ax',0],['ac',0],['bsd',0],['ad',0],['asd',0],['bd',0],['ay',0]];
function sortByLen(a,b){
   if(a[0].length < b[0].length) return -1;
   if(a[0].length > b[0].length) return 1;
   if(a[0] < b[0]) return -1;
   if(a[0] > b[0]) return 1;
   return 0;
}
arr.sort(sortByLen);
console.log(arr);

Upvotes: 0

Related Questions