Reputation: 38
I have a problem with Java static initialization. What I want to do is some type checking with generic constants and to translate between types and type names. So I have some typed constants in interface MC and a hash map in inner class Type to translate names to types. Now when I call
MC.Type.getValue("MInteger")the inner class Type is initialized but not the static constants in the outer class MC so the return value is
null
. How can I get Java to initialize these constants? I could do
static { Type<?> dummy = MC.MBoolean; }
in class Type but isn't there some better way to do this. Or am I doing this totally wrong.
import java.util.HashMap;
import java.util.Map;
interface MC {
public static final Type<Boolean> MBoolean = new Type<>("MBoolean");
public static final Type<Integer> MInteger = new Type<>("MInteger");
public static class Type<T> {
private static final Map<String, Type<?>> types = new HashMap<>();
private final String name;
private Type(String name) {
this.name = name;
types.put(name, this);
}
public String getName() {
return name;
}
public static Type<?> getValue(String name) {
return types.get(name);
}
}
}
public class Main {
public static void main(String[] args) {
System.out.println(MC.Type.getValue("MInteger"));
MC.MBoolean.getName();
System.out.println(MC.Type.getValue("MInteger"));
}
}
Upvotes: 1
Views: 126
Reputation: 1201
The Constructor won't initialize unless you explicitly call MC.MBoolean
. so better you go with the Double brace initialization.
private static final Map<String, Type<?>> types = new HashMap<>() {
{
put(MC.MBoolean.getName(), MC.MBoolean);
put(MC.MInteger.getName(), MC.MInteger);
}
};
Upvotes: 0
Reputation:
You can use either static initializer block:
private static final Map<String, Type<?>> types = new HashMap<>();
static {
types.put(MC.MBoolean.getName(), MC.MBoolean);
types.put(MC.MInteger.getName(), MC.MInteger);
}
or double brace initialization:
private static final Map<String, Type<?>> types = new HashMap<>() {{
put(MC.MBoolean.getName(), MC.MBoolean);
put(MC.MInteger.getName(), MC.MInteger);
}};
First curly braces creates new anonymous subclass of HashMap
, second curly braces are instance initializer block which is executed at construction time (arg-less constructor for anonymous classes).
Upvotes: 1
Reputation: 726479
Since all Type
instances are included in your MC
class, a very direct approach to solving this problem would be to move registration of the class with the Type.types
map from the constructor of Type
to its static initializer:
private static final Map<String, Type<?>> types = new HashMap<>();
static {
types.put(MBoolean.getName(), MBoolean);
types.put(MInteger.getName(), MInteger);
}
private Type(String name) {
this.name = name;
// removed types.put(name, this); from here
}
Upvotes: 1