Reputation: 2992
a = [[1,2,3,4],[5,6],[7,8,9]]
to
name_doesn't_matter = [[11,12,13,14],[15,16],[17,18,19]]
and the number of sublists are the result of user input so the answer should be for any given number of sublists.
Upvotes: 0
Views: 29
Reputation: 8947
Use list comprehensions:
foo = [[1, 2, 3, 4], [5, 6], [7, 8, 9]]
bar = [[x + 10 for x in inner] for inner in foo]
Upvotes: 2