CODEWITHSUNDEEP
javaandroid
alex barnes
alex barnes

Reputation: 33

Java string replace all [url]

I have a String of text that contains various urls surrounded by [url]

For example:

[url]http://www.example.com[/url]

And I want it to read like this:

http://www.example.com

I've tried:

String test = body3.replaceAll("[url]", "");

But I end up still with the brackets []

Upvotes: 0

Views: 3459

Answers (3)

Sanj
Sanj

Reputation: 850

In a regular expression, square brackets are used to specify a range of items to match, so [url] will match the characters, u, r and l.

To match an actual square bracket, you will need to escape it by prefixing it a backslash

\[

But a single backslash will also need to be escaped in java, so you need to precede the square brackets with two backslashes.

So to remove the url block with replaceAll, you could use

    String text = "[url]http://www.example.com[/url]";
    String replaced = text.replaceAll("\\[[url/]+\\]", "");
    System.out.println("replaced = " + replaced);

Upvotes: 0

Sandip Jangra
Sandip Jangra

Reputation: 164

Try this. It seems you want both [url],[/url] to be replaced with empty spaces.

String a = "Example text [url]http://www.example.com[/url] Example text";
String[] b = {"[url]","[/url]"};
String[] c = {"",""};
StringUtils.replaceEach(a,b,c);

result will be : Example text http://www.example.com Example text.

Remember that if you want to replace number of strings with corresponding empty strings or any other string you can do it in above way.

Upvotes: 0

Tim Biegeleisen
Tim Biegeleisen

Reputation: 521249

You could try using a regex replacement:

String input = "Example text [url]http://www.example.com[/url] Example text";
input = input.replaceAll("\\[url\\](.*?)\\[/url\\]", "$1");

Demo here:

Rextester

Upvotes: 1

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