Reputation: 7517
I'm trying to run a piece of R code HERE on R-Fiddle with no success. The code runs very smoothly in R but doesn't run at all HERE on R-Fiddle?
Any advise is appreciated.
alt.hyp = function(N, d){
options(warn = -1) ; d = sort(d)
df = N - 1 ; d.SE = 1/sqrt(N) ; ncp.min = min(d)*sqrt(N) ; ncp.max = max(d)*sqrt(N)
min.d = d.SE*qt(1e-5, df, ncp.min) ; max.d = d.SE*qt(0.99999, df, ncp.max)
for(i in 1:length(d)){
H = curve(dt(d[i]*sqrt(N), df, x*sqrt(N)), min.d, max.d, n = 1e3, xlab = "Effect Size",
ylab = NA, ty = "n", add = i!= 1, bty = "n", yaxt = "n", font.lab = 2)
polygon(H, col = adjustcolor(i, .7), border = NA)
text(d[i], max(H$y), bquote(bolditalic(H[.(i-1)])), pos = 3, xpd = NA)
axis(1, at = d[i], col = i, col.axis = i, font = 2)
segments(d[i], 0, d[i], max(H$y), lty = 3)
}
}
# Example of use:
alt.hyp(N = 30, d = seq(0, 2, .5))
Upvotes: 2
Views: 52
Reputation: 20080
Looks like older version of R is used on the R fiddle.
Anyway, if I redo your script in old style, it works, see here. The only changes are replacement of assignment from =
to <-
and single statement per line.
Code
alt.hyp <- function(N, d) {
options(warn = -1)
d <- sort(d)
df <- N - 1
d.SE <- 1/sqrt(N)
ncp.min <- min(d)*sqrt(N)
ncp.max <- max(d)*sqrt(N)
min.d <- d.SE*qt(1e-5, df, ncp.min)
max.d <- d.SE*qt(0.99999, df, ncp.max)
for(i in 1:length(d)){
H <- curve(dt(d[i]*sqrt(N), df, x*sqrt(N)), min.d, max.d, n = 1e3, xlab = "Effect Size", ylab = NA, ty = "n", add = i!= 1, bty = "n", yaxt = "n", font.lab = 2)
polygon(H, col = adjustcolor(i, .7), border = NA)
text(d[i], max(H$y), bquote(bolditalic(H[.(i-1)])), pos = 3, xpd = NA)
axis(1, at = d[i], col = i, col.axis = i, font = 2)
segments(d[i], 0, d[i], max(H$y), lty = 3)
}
N
}
q <- alt.hyp(N = 30, d = seq(0, 2, .5))
print(q)
And the output in the R Fiddle
Upvotes: 1