CODEWITHSUNDEEP
mysqlsqldatabase
AndyrK
AndyrK

Reputation: 7

How to get count of occurrence of specific value for each row SQL

I have a table named ReviewFact which has the following attributes:

- CategoryID (Primary Key)
- Star_Rating (Primary Key)
- No_of_Reviews

CategoryID refers to specific product, Star_Rating refers to a star rating given by users, No_of_Reviews refers to how many users gave this rating.

I have to write an SQL query which shows the number of 5 star reviews for each category.

I have come up with the following:

SELECT r.CategoryID, r.NUMBER_OF_REVIEWS
FROM REVIEWFACT r
WHERE r.Stars = 5
ORDER BY r.NUMBER_OF_REVIEWS desc;

Using this I get the number of reviews for rows which have 5 star reviews, but not for ones which don't. The ones which don't should have the count as 0. How do I go about solving this?

If there are the following rows in the table:

CategoryID        Star_Rating        No_of_Reviews
1                 5                  10
2                 5                  4
3                 2                  9

The query should return

CategoryID        No_of_Reviews
1                 10
2                 4
3                 0

Upvotes: 0

Views: 1525

Answers (3)

Thorsten Kettner
Thorsten Kettner

Reputation: 94914

Group by category and sum conditionally:

select
  categoryid,
  sum(case when stars = 5 then no_of_reviews else 0 end) as no_of_reviews
from reviewfact 
group by categoryid
order by no_of_reviews;

Upvotes: 0

icoder
icoder

Reputation: 165

Same, with IF statement:

SELECT r.CategoryID, IF(r.Stars = 5, r.NUMBER_OF_REVIEWS, 0) as bestReviews
FROM REVIEWFACT r
ORDER BY r.NUMBER_OF_REVIEWS desc;

Upvotes: 0

Gordon Linoff
Gordon Linoff

Reputation: 1269773

I think you just want a case:

SELECT r.CategoryID,
       (CASE WHEN r.starts = 5 THEN r.NUMBER_OF_REVIEWS ELSE 0 END)
FROM REVIEWFACT r
ORDER BY r.NUMBER_OF_REVIEWS desc;

Upvotes: 1

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