Reputation: 267150
I have a mutable map that contains users:
val userMap = mutable.Map.empty[Int, User] // Int is user.Id
Now I need to load the new users, and add them to the map. I have the following api methods:
def getNewUsers(): Seq[Int]
def getUser(userId: Int): Future[Option[User]]
So I first get all the users I need to load:
val newUserIds: Set[Int] = api.getNewUsers
I now need to load each user, but not sure how to do getUser returns a Future[Option[User]].
I tried this:
api.getNewUsers().map( getUser(_) )
But that returns a Set[Future[Option[User]]]
I'm not sure how to use Set[Future[Option[User]]]
to update my userMap now.
Upvotes: 1
Views: 238
Reputation: 18177
You'll have to wait for all of the Futures to finish. You can use Future.sequence
to transform your Set[Future[_]]
into a Future[Set]
, so you can wait for them all to finish:
val s: Set[scala.concurrent.Future[Some[User]]] = Set(Future(Some(User(1))), Future(Some(User(2))))
val f: Future[Set[Some[User]]] = Future.sequence(s)
f.map(users => users.foreach(u => /* your code here */))
However, using a mutable Map may be dangerous because it's possible to open yourself up to race conditions. Futures are executed in different threads, and if you altering a mutable object's state in different threads, bad things will happen.
Upvotes: 2
Reputation: 816
You can use Future.sequence:
transforms a TraversableOnce[Future[A]] into a Future[TraversableOnce[A]]. Useful for reducing many Futures into a single Future from Scala Future
You can try:
val result : Future[Seq[Option[User]]] =
Future.sequence(
api.getNewUsers().map( getUser )
)
result.andThen {
case Success(users) =>
users.flatten.foreach(u => yourMap += u.id -> u)
}
Upvotes: 1