CODEWITHSUNDEEP
xmlxslt
DMC19
DMC19

Reputation: 927

XSLT - Not applying the template

I'm trying to print on html some XML code with XSLT, but it is not working properly.I'm still newbie and I'm not watching the problem.

This is my XSLT code:

<xsl:output method="html" encoding="UTF-8" />
<xsl:template match="/">
    <div class="form-horizontal">
        <xsl:for-each select="elements/element">
            <xsl:sort data-type="number" select="order" />
            <xsl:if test="@type='OUTPUT'">
                <div class="row">
                    <div class="form-group">
                        <div class="{class}">
                            <xsl:value-of select="value"/>
                        </div>
                    </div>
                </div>
            </xsl:if>
        </xsl:for-each>
    </div>
</xsl:template>
<xsl:template match="i">
    <i>
        <xsl:apply-templates />
    </i>
</xsl:template>
<xsl:template match="b">
    <b>
        <xsl:apply-templates />
    </b>
</xsl:template>
<xsl:template match="u">
    <u>
        <xsl:apply-templates />
    </u>
</xsl:template>
<xsl:template match="del">
    <del>
        <xsl:apply-templates />
    </del>
</xsl:template>

And this is my XML example code:

<elements>
    <element type='OUTPUT'>
        <value>
            <b>
                <u>Personal information</u>
            </b>
        </value>
        <class>col-md-12 output</class>
        <order>2</order>
    </element>
</elements>

All works fine except the <b> and <u> tags.

This is what I'm obtaining:

enter image description here

My expected Output:

<div class="row">
    <div class="form-group">
        <div class="col-md-12 output">
            <b>
                <u>Personal information</u>
            </b>
        </div>
    </div>
</div>

Someone knows where is the mistake?

Thanks in advance.

Upvotes: 0

Views: 58

Answers (2)

zx485
zx485

Reputation: 29022

You are missing an xsl:apply-templates in your first template.
Change it to

<div class="{class}">
    <xsl:apply-templates  />
    <xsl:value-of select="value"/>
</div>

Upvotes: 1

Martin Honnen
Martin Honnen

Reputation: 167571

You will have to use xsl:apply-templates if you want your templates to be applied e.g. instead of 

                        <xsl:value-of select="value"/>

use

  <xsl:apply-templates select="value"/>

Upvotes: 3

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