CODEWITHSUNDEEP
php
corporalpoon
corporalpoon

Reputation: 229

Format a variable after a character in a string

I'm using a variable called $contact_location a few times.

It works fine up until I need to use it for a URL.

Example string:

"Hello, from $contact_location, please visit www.ourwebsite.com/$contact_location"

output: Hello, from New Mexico, please visit www.ourwebsite.com/New Mexico.

Needed Output: Hello, from New Mexico, please visit www.ourwebsite.com/new-mexico

Is there a way to format a variable only if it comes after something like ".com/"

The url should read www.ourwebsite.com/new-mexico

I know how to str_replace

str_replace(" ","-",$contact_location);

Upvotes: 1

Views: 70

Answers (2)

Abe
Abe

Reputation: 1415

Try this:

<?php
function formatUrl($msg)
{    
    $pattern = '/www\..*/';
    preg_match($pattern, $msg, $matches);
    return preg_replace($pattern, strtolower(str_replace(' ','-',$matches[0])),$msg);
}

$contact_location = 'New Mexico';
$msg = formatUrl("Hello, from $contact_location, please visit www.ourwebsite/$contact_location");
var_dump($msg);

By using preg_match and preg_replace, you can easilly perform a replacement in string based on a pattern.

I was assuming then you're looking for a web site content to change, so, my pattern is '/www\..*/'. But, if you want to change it, to .com as mentioned on your question, just replace $pattern value to your desired match.

Here, a simple regex trainning.

Upvotes: 1

Ghanshyam Dekavadiya
Ghanshyam Dekavadiya

Reputation: 153

$text = "Your text will be here www.yourdomain.com";
$contact_location = "new-maxico";
if (stripos($text, ".com") !== false) {
   $text = $text . "/" . $contact_location;
}

This will help you for sure

Upvotes: 0

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