CODEWITHSUNDEEP
javascriptstringfunctionsubstringsubstr
Rataiczak24
Rataiczak24

Reputation: 1042

Removing Text from Part of String

I am needing to remove text within different strings.

I need a function that will make the following...

test: example1
preview: sample2
sneakpeak: model3
view: case4

...look like this:

example1
sample2
model3
case4

I have tried using the substr and substring functions but was not able to find a solution.

I used selected.substr(0, selected.indexOf(':')) but all that returned to me was the text before the colon. selected is the variable that contains the string of text.

With the strings being different lengths, it's something that cannot be hardcoded either. Any suggestions?

Upvotes: 2

Views: 1259

Answers (4)

Nebojsa Nebojsa
Nebojsa Nebojsa

Reputation: 1459

You can do it with regex /[a-z]*:\s/gim
See the example snippet code below

var string = "test: example1\n\
preview: sample2\n\
sneakpeak: model3\n\
view: case4";

var replace = string.replace(/[a-z]*:\s/gim, "");

console.log(replace);

The output will be:

example1
sample2
model3
case4

Upvotes: 0

ibrahim mahrir
ibrahim mahrir

Reputation: 31682

substring takes two parameters: the start of the cut and the end of the cut (optional).

substr takes two parameters: the start of the cut and the length of the cut (optional).

You should use substr with one parameter only, the start of the cut (omitting the second parameter will make substr cut from the start index to the end):

var result = selected.substr(selected.indexOf(':'));

You may want to trim the result to remove the spaces around result:

var result = selected.substr(selected.indexOf(':')).trim();

Upvotes: 2

Steven Scaffidi
Steven Scaffidi

Reputation: 2307

Try this:

function getNewStr(str, delimeter = ':') {


  return str.substr( str.indexOf(delimeter) + 1).trim();


}

Upvotes: 0

Dinesh undefined
Dinesh undefined

Reputation: 5546

Use split function. split will return an array. To remove spaces use trim()

var res = "test: example1".split(':')[1].trim();

console.log(res);

Upvotes: 2

Related Questions