CODEWITHSUNDEEP
javastringfor-loopstringindexoutofbounds
Christopher
Christopher

Reputation: 21

StringIndexOutOfBoundsException unclear

My goal is to return a string that is composed of each letter as long as the letter is later on in the alphabet than its previous one, assuming the word is lowercase. Problem is, I can't even test this out because I am getting an error (in the title) and I am unsure of how it is occurring. May I have some assistance?

Here is my code:

class Main {
    static String alphabetical(String str)
    {
      String alpha="abcdefghijklmnopqrstuvwxyz";
      String betical="";
        for(int k=0;k<str.length();k++){
          for (int i=0;k<alpha.length();i++){
            if(str.charAt(k)>=alpha.charAt(i)){
              betical+=str.charAt(k);
            }
          }
        }
        return betical;
    }
    //test case below (dont change):
    public static void main(String[] args){
        System.out.println(alphabetical("adatplqzh")); //result should be "adtz"
    }
}

Upvotes: 2

Views: 99

Answers (2)

virag raiyani
virag raiyani

Reputation: 1

Your inner loop looks wrong,

for (int i=0;k<alpha.length();i++){

should be for (int i=0;i<alpha.length();i++)

Upvotes: 0

Umer Waqas - nextjs python
Umer Waqas - nextjs python

Reputation: 5283

As per comment you should change for (int i=0; k< alpha.length(); i++) to for(int i=0; i< alpha.length(); i++) and the modify your condition, 

 if(str.charAt(k)==alpha.charAt(i)){    
                   betical+=str.charAt(k);
                }

and it will give the required output

Upvotes: 2

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