CODEWITHSUNDEEP
rdataframemapply
Gia
Gia

Reputation: 1

How to use mapply() to extract a certain column of a certain data frame in a list?

I am having some trouble trying to figure this out.

I have a list of 3 dataframes:

list_of_dataframes = list(iris, trees, mtcars)

I need to use mapply to return a list where:

Upvotes: 0

Views: 137

Answers (2)

www
www

Reputation: 39154

We can also use the map2 function from the purrr package to loop through the list of data frame (on the .x argument) and the index of column 1:3 (on the .y argument).

list_of_dataframes <- list(iris, trees, mtcars) 

library(purrr)

map2(list_of_dataframes, 1:3, ~.x[, .y])
[[1]]
  [1] 5.1 4.9 4.7 4.6 5.0 5.4 4.6 5.0 4.4 4.9 5.4 4.8 4.8 4.3 5.8 5.7 5.4 5.1 5.7 5.1
 [21] 5.4 5.1 4.6 5.1 4.8 5.0 5.0 5.2 5.2 4.7 4.8 5.4 5.2 5.5 4.9 5.0 5.5 4.9 4.4 5.1
 [41] 5.0 4.5 4.4 5.0 5.1 4.8 5.1 4.6 5.3 5.0 7.0 6.4 6.9 5.5 6.5 5.7 6.3 4.9 6.6 5.2
 [61] 5.0 5.9 6.0 6.1 5.6 6.7 5.6 5.8 6.2 5.6 5.9 6.1 6.3 6.1 6.4 6.6 6.8 6.7 6.0 5.7
 [81] 5.5 5.5 5.8 6.0 5.4 6.0 6.7 6.3 5.6 5.5 5.5 6.1 5.8 5.0 5.6 5.7 5.7 6.2 5.1 5.7
[101] 6.3 5.8 7.1 6.3 6.5 7.6 4.9 7.3 6.7 7.2 6.5 6.4 6.8 5.7 5.8 6.4 6.5 7.7 7.7 6.0
[121] 6.9 5.6 7.7 6.3 6.7 7.2 6.2 6.1 6.4 7.2 7.4 7.9 6.4 6.3 6.1 7.7 6.3 6.4 6.0 6.9
[141] 6.7 6.9 5.8 6.8 6.7 6.7 6.3 6.5 6.2 5.9

[[2]]
 [1] 70 65 63 72 81 83 66 75 80 75 79 76 76 69 75 74 85 86 71 64 78 80 74 72 77 81 82
[28] 80 80 80 87

[[3]]
 [1] 160.0 160.0 108.0 258.0 360.0 225.0 360.0 146.7 140.8 167.6 167.6 275.8 275.8
[14] 275.8 472.0 460.0 440.0  78.7  75.7  71.1 120.1 318.0 304.0 350.0 400.0  79.0
[27] 120.3  95.1 351.0 145.0 301.0 121.0

Upvotes: 2

Rich Scriven
Rich Scriven

Reputation: 99331

If you want atomic vectors returned, it would be

mapply("[", list_of_dataframe, 1:3)

But if you want single column data frames returned, you can do

Map("[", list_of_dataframe, 1:3)

or just use SIMPLIFY = FALSE in mapply(). And alternatively, you can use subset().

mapply(subset, list_of_dataframe, select = 1:3)

Upvotes: 2

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