CODEWITHSUNDEEP
bash
dagda1
dagda1

Reputation: 28760

start more than one process at the same time with bash script

I have the following bash script:

#!/bin/bash

set -o errexit # Exit on error

# Enable script to run from anywhere
cd "$(dirname ${BASH_SOURCE[0]})"

root=$(pwd)

cd "../../../"
source ./somebashscript

cd "../../../..."

source ./otherbashscript

both source commands will launch their own process.

How do I launch both processes from the same bash script?

Upvotes: 1

Views: 44

Answers (1)

Chen A.
Chen A.

Reputation: 11280

Using & at the end of the command starts the process in the background.

cd "../../../"
source ./somebashscript &

cd "../../../..."

source ./otherbashscript &

You may want to redirect the output of the scripts to somewhere else, otherwise everything will be printed to your screen. You can do that by adding > file.log if you want to log the output, or > /dev/null if you want to drop it

source ./somebashscript > /dev/null &

Upvotes: 1

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