CODEWITHSUNDEEP
scalaplayframework
Blankman
Blankman

Reputation: 267000

How to manually create a class with a configuration for testing

I have a class that I use in playframework that automatically injects the dependency.

How can I create this class "manually" in my test code:

class AppConfog @Inject()(c: Configuration) {
   val supportEmail = c.getString("app.email").get
   ...
}

I'm not sure how to get a Configuration class to pass into it.

I know I can create an inline config like:

  val config =
    """
    akka {
      loglevel = "WARNING"
    }
    """

  ConfigFactory.parseString(config)

How do I get a Configuration from a config?

Upvotes: 0

Views: 116

Answers (1)

insan-e
insan-e

Reputation: 3921

I think that Play's Configuration just wraps Typesafe Config that you get with your ConfigFactory.parseString(config). See here.
So you should be able to do this:

val underlying =  ConfigFactory.parseString(config)
val configuration = Configuration(underlying)
val mockAppConfog = new AppConfog(configuration)

Upvotes: 2

Related Questions