Reputation: 965
Re-writing the question since named capturing groups are not the main issue.
I have the following regex now:
/([a-zA-Z ]*)([0-9]*)/g
The code is working now fine but var m = /([a-zA-Z ]*)([0-9]*)/g.exec('Ashok : 9830011245')
is only giving me the Ashok as the result.
m[0]: "Ashok"
m[1]: "Ashok"
m[2]: ""
Sample Strings I need to work it on:
var strings = [
"Ashok : 9812340245",
"Amit Singh :\nChakmir 9013123427\n\nHitendra Singh:\n\nM. : 9612348943",
"ANIL AGARWAL : \n09331234728\n09812340442\nMAYANK AGARWAL : \n09123416042",
"JAGDISH SINGH : 098123452187 \n09830111234",
"MD QYAMUDDIN : 09433186333,\n09477215123\nMD TAJUDDIN : \n09831429111\nGYASUDDIN ANSARI :\n08961383686 \nMD BABUDDIN : \n09433336456 \n09903568555\nJAWE",
"Viay Singh : 9330938789,\nBijay Singh : 9330938222",
"Nilu : 09830161000,\n09331863222,\n09830071333,\nSantosh Upadhayay : 09831379555,\n09331727858,\n09830593322"
];
Please guide.
Upvotes: 1
Views: 172
Reputation: 626690
It seems you may extract all the substrings you need with
/^([^:0-9\n]+)\s*(?::\s*)?([0-9]*)/gm
See the regex demo.
Details
^
- start of the line (as m
enables the multiline mode)([^:0-9\n]+)
- 1 or more chars other than :
, digits and newline\s*
- 1 or more whitespaces(?::\s*)?
- an optional sequence of :
and 0+ whitespaces([0-9]*)
- zero or more digits.JS demo:
var strings = [
"Ashok : 9812340245",
"Amit Singh :\nChakmir 9013123427\n\nHitendra Singh:\n\nM. : 9612348943",
"ANIL AGARWAL : \n09331234728\n09812340442\nMAYANK AGARWAL : \n09123416042",
"JAGDISH SINGH : 098123452187 \n09830111234",
"MD QYAMUDDIN : 09433186333,\n09477215123\nMD TAJUDDIN : \n09831429111\nGYASUDDIN ANSARI :\n08961383686 \nMD BABUDDIN : \n09433336456 \n09903568555\nJAWE",
"Viay Singh : 9330938789,\nBijay Singh : 9330938222",
"Nilu : 09830161000,\n09331863222,\n09830071333,\nSantosh Upadhayay : 09831379555,\n09331727858,\n09830593322"
];
var regex = /^([^:0-9\n]+)\s*(?::\s*)?([0-9]*)/gm;
for (var s of strings) {
console.log("Looking in: ", s, "\n--------------------------");
console.log(s.match(regex));
}
// To output groups:
console.log("====Outputting groups====");
for (var s of strings) {
while(m=regex.exec(s))
console.log(m[1].trim(), ";", m[2]);
}
Upvotes: 1