CODEWITHSUNDEEP
phparrays
user200
user200

Reputation: 301

If the array is empty I don't want to show results in PHP

I have code like this

   <?php 

   global $DB; 
   $useridQry=''; 
  $login_id = $_SESSION['USER']->id; 

   if( $_SESSION['idnumber'] == 3 ) 
   { 

    } 
 elseif( $_SESSION['idnumber'] == 2 ) 
 { 
    $records=$DB->get_records_sql("select * from {user} where 
    maildigest=$login_id"); 
   print_r($records);
 if(empty($records) && count($records){
 { 
   $userIds=''; 
   foreach($records as $row) 
 { 
  $userIds="'".$row->id."'"; 
 } 
 //$useridQry = " and st.userid IN ($userIds)"; 
 } 
 } 
  else 
  { 
   $useridQry = " and st.userid = $login_id"; 
  }

so what happened is if is there any records it will show in table 

print_r($records);

when I use print,

But if is there no data it showing empty array like this Array ( )

so when it showing empty array also it showing data in my tables..i don't want to show data if it is empty array..

can anyone help me how to do that,

thanks in advance..

Upvotes: 1

Views: 315

Answers (3)

delboy1978uk
delboy1978uk

Reputation: 12375

Look at this snippet: https://3v4l.org/CjTuv

   $x = [];
    print_r($x);
    if (count($x)) {
        echo 'yes';
    }

print_r() will always display output. It's usually just for debugging. If you don't want Array( ) displaying, either remove the print_r or move it inside your if statement.

Upvotes: 3

a.anon
a.anon

Reputation: 158

Try this:

if(!empty($records) && count($records) > 0){ ...

instead of:

if(count($records)){

Upvotes: -1

Washipp
Washipp

Reputation: 1

How about checking, if the array is empty?

if (empty($playerlist)) {
     // list is empty.
}

Upvotes: -1

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